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  • HDU 2952 Counting Sheep(DFS)

    题目链接

    Problem Description
    A while ago I had trouble sleeping. I used to lie awake, staring at the ceiling, for hours and hours. Then one day my grandmother suggested I tried counting sheep after I'd gone to bed. As always when my grandmother suggests things, I decided to try it out. The only problem was, there were no sheep around to be counted when I went to bed.

    Creative as I am, that wasn't going to stop me. I sat down and wrote a computer program that made a grid of characters, where # represents a sheep, while . is grass (or whatever you like, just not sheep). To make the counting a little more interesting, I also decided I wanted to count flocks of sheep instead of single sheep. Two sheep are in the same flock if they share a common side (up, down, right or left). Also, if sheep A is in the same flock as sheep B, and sheep B is in the same flock as sheep C, then sheeps A and C are in the same flock.

    Now, I've got a new problem. Though counting these sheep actually helps me fall asleep, I find that it is extremely boring. To solve this, I've decided I need another computer program that does the counting for me. Then I'll be able to just start both these programs before I go to bed, and I'll sleep tight until the morning without any disturbances. I need you to write this program for me.
     
    Input
    The first line of input contains a single number T, the number of test cases to follow.

    Each test case begins with a line containing two numbers, H and W, the height and width of the sheep grid. Then follows H lines, each containing W characters (either # or .), describing that part of the grid.
     
    Output
    For each test case, output a line containing a single number, the amount of sheep flock son that grid according to the rules stated in the problem description.
    Notes and Constraints
    0 < T <= 100
    0 < H,W <= 100
     
    Sample Input
    2 4 4
    #.#.
    .#.#
    #.##
    .#.#
    3 5
    ###
    .#.
    .#.
    .#.
    ###
     
    Sample Output
    6 3

    题解:题目描述什么的一大段废话,直接看输入输出,发现是一个经典的DFS连通块问题。

    #include <cstdio>
    #include <iostream>
    #include <string>
    #include <sstream>
    #include <cstring>
    #include <stack>
    #include <queue>
    #include <algorithm>
    #include <cmath>
    #include <map>
    #define ms(a) memset(a,0,sizeof(a))
    #define msp memset(mp,0,sizeof(mp))
    #define msv memset(vis,0,sizeof(vis))
    using namespace std;
    //#define LOCAL
    char mp[120][120];
    int n,m;
    int ans;
    int dir[4][2]={{0,1},{0,-1},{1,0},{-1,0}};
    void dfs(int x,int y)
    {
        for(int i=0;i<4;i++)
        {
            int nx=x+dir[i][0],ny=y+dir[i][1];
            if(nx>=0&&nx<n&&ny>=0&&ny<m)
            {
                if(mp[nx][ny]=='#')
                {
                    mp[nx][ny]='.';
                    dfs(nx,ny);
                }
            }
        }
        return;
    }
    int main()
    {
    #ifdef LOCAL
        freopen("in.txt", "r", stdin);
    #endif // LOCAL
        //Start
        int N;
        cin>>N;
        while(N--)
        {
            cin>>n>>m;
            msp,ans=0;
            for(int i=0; i<n; i++)cin>>mp[i];
            for(int i=0; i<n; i++)
            for(int j=0; j<m; j++)
            if(mp[i][j]=='#')
            {
                mp[i][j]='.';
                ans++;
                dfs(i,j);
            }
            printf("%d
    ",ans);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/gpsx/p/5171175.html
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