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  • [LeetCode] 1200. Minimum Absolute Difference 最小绝对差


    Given an array of distinct integers arr, find all pairs of elements with the minimum absolute difference of any two elements.

    Return a list of pairs in ascending order(with respect to pairs), each pair [a, b] follows

    • a, b are from arr
    • a < b
    • b - a equals to the minimum absolute difference of any two elements in arr

    Example 1:

    Input: arr = [4,2,1,3]
    Output: [[1,2],[2,3],[3,4]]
    Explanation: The minimum absolute difference is 1. List all pairs with difference equal to 1 in ascending order.
    

    Example 2:

    Input: arr = [1,3,6,10,15]
    Output: [[1,3]]
    

    Example 3:

    Input: arr = [3,8,-10,23,19,-4,-14,27]
    Output: [[-14,-10],[19,23],[23,27]]
    

    Constraints:

    • 2 <= arr.length <= 10^5
    • -10^6 <= arr[i] <= 10^6

    这道题给了一个没有重复数字的整型数组,现在让找出差的绝对值最小的数对儿。既然是 Easy 的身价,那么就没有太 Fancy 的解法,为了更方便的找出差的绝对值最小的数对儿,先给数组进行排序,这样最小差值一定会出现在相邻的两个数字之间。接下来就是遍历所有相邻的两个数字,维护一个最小值 mn,若当前差值 diff 小于等于 mn,则进行进一步操作,二者中唯一不同的是当 diff 小于 mn 时,结果 res 需要清空。然后将 mn 更新为 diff,并把当前数组对儿加入到结果 res 中即可,参见代码如下:


    class Solution {
    public:
        vector<vector<int>> minimumAbsDifference(vector<int>& arr) {
            vector<vector<int>> res;
            int n = arr.size(), mn = INT_MAX;
            sort(arr.begin(), arr.end());
            for (int i = 1; i < n; ++i) {
                int diff = arr[i] - arr[i - 1];
                if (diff <= mn) {
                    if (diff < mn) res.clear();
                    mn = diff;
                    res.push_back({arr[i - 1], arr[i]});   
                }
            }
            return res;
        }
    };
    

    Github 同步地址:

    https://github.com/grandyang/leetcode/issues/1200


    参考资料:

    https://leetcode.com/problems/minimum-absolute-difference/

    https://leetcode.com/problems/minimum-absolute-difference/discuss/388289/Java-sorting-beats-100-explained


    LeetCode All in One 题目讲解汇总(持续更新中...)

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  • 原文地址:https://www.cnblogs.com/grandyang/p/15163992.html
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