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  • [LintCode] Wiggle Sort 扭动排序

    Given an unsorted array nums, reorder it in-place such that

    nums[0] <= nums[1] >= nums[2] <= nums[3]....
    Notice

    Please complete the problem in-place.

    Example
    Given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4].

    LeetCode上的原题,请参见我之前的博客Wiggle Sort

    解法一:

    class Solution {
    public:
        /**
         * @param nums a list of integer
         * @return void
         */  
        void wiggleSort(vector<int>& nums) {
            sort(nums.begin(), nums.end());
            for (int i = 1; i < nums.size(); ++i) {
                if (i % 2 == 0) {
                    swap(nums[i], nums[i - 1]);
                }
            }
        }
    };

    解法二:

    class Solution {
    public:
        /**
         * @param nums a list of integer
         * @return void
         */  
        void wiggleSort(vector<int>& nums) {
            for (int i = 1; i < nums.size(); ++i) {
                if ((i % 2 == 1 && nums[i] < nums[i - 1]) || (i % 2 == 0 && nums[i] > nums[i - 1])) {
                    swap(nums[i], nums[i - 1]);
                } 
            }
        }
    };
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  • 原文地址:https://www.cnblogs.com/grandyang/p/5500067.html
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