zoukankan      html  css  js  c++  java
  • 1036. Boys vs Girls (25)

    This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

    Input Specification:

    Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.

    Output Specification:

    For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF-gradeM. If one such kind of student is missing, output "Absent" in the corresponding line, and output "NA" in the third line instead.

    Sample Input 1:

    3
    Joe M Math990112 89
    Mike M CS991301 100
    Mary F EE990830 95
    

    Sample Output 1:

    Mary EE990830
    Joe Math990112
    6
    

    Sample Input 2:

    1
    Jean M AA980920 60
    

    Sample Output 2:

    Absent
    Jean AA980920
    NA

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    struct Student{
    	char name[11];
    	char id[11];
    	int grade;
    };
    Student m_stu;
    Student f_stu;
    int main(){
    	char name[11];
    	char gender;
    	char id[11];
    	int grade;
    	m_stu.grade=101;
    	f_stu.grade=-1;
    	int n;
    	scanf("%d",&n);
    	int i,j;
    	for(i=0;i<n;i++){
    		getchar();
    		scanf("%s %c %s %d",name,&gender,id,&grade);
    		if(gender == 'M'&&grade<m_stu.grade){
    			strcpy(m_stu.name,name);
    			strcpy(m_stu.id,id);
    			m_stu.grade=grade;
    			//cout<<grade<<endl;
    		}else if(gender == 'F'&&grade>f_stu.grade){
    			strcpy(f_stu.name,name);
    			strcpy(f_stu.id,id);
    			f_stu.grade=grade;
    		}
    	}
    	if(f_stu.grade==-1 && m_stu.grade == 101){
    		printf("Absent
    Absent
    ");
    		printf("NA
    ");
    	}else if(f_stu.grade==-1&&m_stu.grade != 101){
    		printf("Absent
    %s %s
    ",m_stu.name,m_stu.id);
    		printf("NA
    ");
    	}else if(m_stu.grade == 101&&f_stu.grade!=-1){
    		printf("%s %s
    Absent
    ",f_stu.name,f_stu.id);
    		printf("NA
    ");
    	}else {
    		printf("%s %s
    ",f_stu.name,f_stu.id);
    		printf("%s %s
    ",m_stu.name,m_stu.id);
    		printf("%d
    ",f_stu.grade-m_stu.grade);
    	}
    	return 0;
    }
    

      

  • 相关阅读:
    2021暑假模拟赛6
    2021暑假模拟赛5
    2021暑假模拟赛4
    2021暑假模拟赛3
    2021暑假模拟赛2
    umi提速方案之 mfsu
    Nginx (可为容器)配置 BasicAuth 与访问
    Mango 漫画管理器体验
    blivechat 在 OBS 中使用 BasicAuth URL 登录
    Electron 实现最小化到托盘
  • 原文地址:https://www.cnblogs.com/grglym/p/7738835.html
Copyright © 2011-2022 走看看