luogu 2993 [FJOI2014]最短路径树问题 Dijkstra+点分治

挺简单的，但是给人一种把两个问题强行弄到一起的感觉. 

十分不好写. 

Code: 

#include <queue> 
#include <cstdio> 
#include <vector>   
#include <algorithm>  
#define N 100007    
#define ll long long 
#define inf 1000000004  
#define setIO(s) freopen(s".in","r",stdin)  
using namespace std;    
int K,n,m;  
namespace tree 
{  
	ll answer; 
	int edges,root,sn,maxdep,tl,best; 
	int hd[N],to[N],nex[N],val[N]; 
	int size[N],mx[N],vis[N],f[N],g[N],bu[N],cntf[N],cntg[N];    
	void addedge(int u,int v,int c)
	{ 
		nex[++edges]=hd[u],hd[u]=edges,to[edges]=v,val[edges]=c;     
	}
	void getroot(int u,int ff) 
	{
		size[u]=1,mx[u]=0; 
		for(int i=hd[u];i;i=nex[i]) 
		{
			int v=to[i]; 
			if(!vis[v]&&v!=ff) 
				getroot(v,u), size[u]+=size[v], mx[u]=max(mx[u], size[v]); 
		} 
		mx[u]=max(mx[u],sn-size[u]); 
		if(mx[u]<mx[root]) root=u; 
	}  
	void dfs(int u,int ff,int depth,int p) 
	{      
		if(depth>=g[p]) 
		{ 
			if(depth==g[p]) ++cntg[p];    
			else {
				if(!g[p]) bu[++tl]=p;    
				g[p]=depth, cntg[p]=1;   
			}
		}   
		for(int i=hd[u];i;i=nex[i]) 
		{
			int v=to[i]; 
			if(v==ff||vis[v]) continue;   
			dfs(v,u,depth+val[i],p+1);   
		}
	}  
	void calc(int u) 
	{  
		int i,j,cur=0;   
		cntf[0]=1,tl=0;             
		for(i=hd[u];i;i=nex[i]) 
		{
			int v=to[i]; 
			if(vis[v]) 
				continue;     
			dfs(v,u,val[i],1);    
			for(j=cur+1;j<=tl;++j)  
			{  
				if(K-1<bu[j]) continue;     
				if(g[bu[j]]+f[K-bu[j]-1]==best) 
				{ 
					answer+=(ll)(cntg[bu[j]]*cntf[K-bu[j]-1]);   
				}
				else if(g[bu[j]]+f[K-bu[j]-1]>best) 
				{ 
					best=g[bu[j]]+f[K-bu[j]-1];       
					answer=(ll)(cntg[bu[j]]*cntf[K-bu[j]-1]);   
				}   
			}    
			for(j=cur+1;j<=tl;++j) 
			{
				if(g[bu[j]]==f[bu[j]]) cntf[bu[j]]+=cntg[bu[j]];  
				else if(g[bu[j]]>f[bu[j]]) 
				{
					cntf[bu[j]]=cntg[bu[j]];  
					f[bu[j]]=g[bu[j]]; 
				}
			} 
			for(j=cur+1;j<=tl;++j) 
				cntg[bu[j]]=g[bu[j]]=0;     
			cur=tl;    
		}      
		for(i=1;i<=cur;++i) cntf[bu[i]]=cntg[bu[i]]=f[bu[i]]=g[bu[i]]=0;       
	}
	void solve(int u) 
	{    
		vis[u]=1; 
		calc(u); 
		for(int i=hd[u];i;i=nex[i]) 
			if(!vis[to[i]]) 
				sn=size[to[i]],root=0,getroot(to[i],u),solve(root);     
	}  
	int main() 
	{  
		root=0,mx[0]=inf,sn=n; 
		getroot(1,0),solve(root);
		printf("%d %lld
",best,answer);            
		return 0; 
	}
}; 
namespace Dijkstra 
{    
	int d[N],done[N],vis[N];    
	struct Edge 
	{
		int to,val;  
		Edge(int to=0,int val=0):to(to),val(val){}   
	};  
	bool cmp(Edge a,Edge b) 
	{
		return a.to<b.to; 
	}
	struct Node 
	{
		int u,dis; 
		Node(int u=0,int dis=0):u(u),dis(dis){}    
		bool operator<(Node a)const 
		{
			return a.dis<dis;    
		}
	};    
	priority_queue<Node>q;    
	vector<Edge>G[N];        
	void add(int u,int v,int c) 
	{
		G[u].push_back(Edge(v,c));      
	}   
	void dfs(int u) 
	{ 
		vis[u]=1;    
		for(int i=0;i<G[u].size();++i) 
			if(!vis[G[u][i].to]&&d[u]+G[u][i].val==d[G[u][i].to]) 
			{
				vis[G[u][i].to]=1; 
				tree::addedge(u,G[u][i].to,G[u][i].val);  
				tree::addedge(G[u][i].to,u,G[u][i].val);       
				dfs(G[u][i].to);       
			}
	}
	void build_tree() 
	{  
		int i; 
		for(i=0;i<=n;++i) d[i]=inf; 
		q.push(Node(1,0)), d[1]=0; 
	    while(!q.empty()) 
	    {
	    	Node e=q.top();q.pop(); 
	    	int u=e.u;   
	    	if(done[u]) continue; 
	    	done[u]=1; 
	    	for(i=0;i<G[u].size();++i) 
	    	{
	    		Edge h=G[u][i]; 
	    		if(d[h.to]>d[u]+h.val) 
	    		{
	    			d[h.to]=d[u]+h.val; 
	    			q.push(Node(h.to,d[h.to]));             
	    		}
	    	}
	    }   
	    for(i=1;i<=n;++i) sort(G[i].begin(),G[i].end(),cmp);  
	    dfs(1);    
	}
}; 
int main() 
{
	int i,j; 
	// setIO("input");        
	scanf("%d%d%d",&n,&m,&K);      
	for(i=1;i<=m;++i) 
	{
		int a,b,c; 
		scanf("%d%d%d",&a,&b,&c);
		Dijkstra::add(a,b,c); 
		Dijkstra::add(b,a,c);      
	} 
	Dijkstra::build_tree();    
	tree::main();        
	return 0; 
}