简简单单二分答案,n和m不要写反
Code:
#include<cstdio>
#include<algorithm>
using namespace std;
const int maxn = 1000000 + 3;
int l,m,n,dis[maxn];
inline bool check(int tps)
{
int pre = 0, cnt = 0, i;
for(i = 1;i <= n; ++i)
{
if(dis[i] - pre >= tps) pre = dis[i];
else ++cnt;
}
if(cnt > m || l - pre < tps)return 0;
return 1;
}
int main()
{
// freopen("in.txt","r",stdin);
scanf("%d%d%d",&l,&n,&m);
for(int i = 1;i <= n;++i)scanf("%d",&dis[i]);
int L = 0, R = l, ans = 0;
while(L <= R)
{
int mid = (L + R) >> 1;
if(check(mid)) ans = mid, L = mid + 1;
else R = mid - 1;
}
printf("%d",ans);
return 0;
}