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  • 模板 高精度运算

    联赛前终于把高精度的坑填上了

    读入写错了导致第一交爆5了..

    贴上丑陋的压4位代码

      1 #include <queue>
      2 #include <cstdio>
      3 #include <cstring>
      4 #include <algorithm>
      5 #define N 26000
      6 #define maxn 10000
      7 #define inf 66666666
      8 #define idx(x) (x-'0')
      9 using namespace std;
     10 
     11 int n,cte,num;
     12 struct bignum{
     13     int a[N],neg,len,res;
     14     friend bignum operator - (bignum &a,bignum &b);
     15     friend bignum operator + (bignum &a,bignum &b);
     16     friend int operator != (const bignum &a,const bignum &b)
     17     {
     18         if(a.len!=b.len) return 1;
     19         for(int i=1;i<=min(a.len,b.len);i++)
     20             if(a.a[i]!=b.a[i]) return 1;
     21         return 0; 
     22     }
     23     friend int operator <= (const bignum &a,const bignum &b)
     24     {
     25         if(a.len>b.len) return 0;
     26         if(b.len>a.len) return 1;
     27         for(int i=a.len;i>=1;i--)
     28             if(a.a[i]>b.a[i]) return 0;
     29             else if(a.a[i]<b.a[i]) return 1;
     30         return 1;
     31     }
     32     friend bignum operator + (bignum &a,bignum &b)
     33     {
     34         if(a.neg&&!b.neg){
     35             a.neg^=1;
     36             return b-a;   
     37         }else if(!a.neg&&b.neg){
     38             b.neg^=1;
     39             return a-b;
     40         }
     41         bignum ret;
     42         memset(&ret,0,sizeof(ret));
     43         if(a.neg&&b.neg) ret.neg^=1;
     44         ret.len=max(a.len,b.len);
     45         for(int i=1;i<=ret.len;i++)
     46         {
     47             ret.a[i]+=a.a[i]+b.a[i];
     48             if(ret.a[i]>=maxn) 
     49                 ret.a[i]-=maxn,ret.a[i+1]++;
     50         }
     51         if(ret.a[ret.len+1]!=0) ret.len++;
     52         while(!ret.a[ret.len])
     53             ret.len--;
     54         return ret;
     55     }
     56     friend bignum operator - (bignum &a,bignum &b)
     57     {   
     58         if(a.neg&&!b.neg){
     59             b.neg^=1;
     60             return a+b;   
     61         }else if(!a.neg&&b.neg){
     62             b.neg^=1;
     63             return a+b;
     64         }
     65         bignum ret;
     66         memset(&ret,0,sizeof(ret));
     67         if(b<=a) ret.neg=0;
     68         else swap(a,b),ret.neg^=1;
     69         if(a.neg&&b.neg) 
     70             swap(a,b),ret.neg^=1;
     71         ret.len=a.len;
     72         for(int i=1;i<=a.len;i++)
     73         {
     74             ret.a[i]+=a.a[i]-b.a[i];
     75             if(ret.a[i]<0) 
     76                 ret.a[i+1]--,ret.a[i]+=maxn;
     77         }
     78         while(!ret.a[ret.len])
     79             ret.len--;
     80         return ret;
     81     } 
     82     friend bignum operator * (bignum &a,bignum &b)
     83     {
     84         bignum ret;
     85         memset(&ret,0,sizeof(ret));
     86         if(a.neg) ret.neg^=1;
     87         if(b.neg) ret.neg^=1;
     88         for(int i=1;i<=a.len;i++)
     89             for(int j=1;j<=b.len;j++){
     90                 ret.a[i+j-1]+=a.a[i]*b.a[j];
     91                 if(ret.a[i+j-1]>=maxn){
     92                     ret.a[i+j]+=ret.a[i+j-1]/maxn;
     93                     ret.a[i+j-1]%=maxn;}
     94                 }
     95         ret.len=a.len+b.len;
     96         while(!ret.a[ret.len])
     97             ret.len--;
     98         return ret;
     99     }
    100     friend bignum operator / (bignum &a,int b)
    101     {
    102         bignum ret;
    103         memset(&ret,0,sizeof(ret));
    104         //memset(&ret,&x,sizeof(x));
    105         int sum=0;
    106         for(int i=a.len;i>=1;i--){
    107             sum=sum*maxn+a.a[i];
    108             ret.a[i]=sum/b;
    109             sum%=b;
    110         }ret.len=a.len,ret.res=sum;
    111         while(!ret.a[ret.len]&&ret.len>1)
    112             ret.len--;
    113         return ret;
    114     }
    115 };
    116 char str[N*4];
    117 bignum read()
    118 {
    119     scanf("%s",str);
    120     bignum ret;
    121     int mi=0;
    122     memset(&ret,0,sizeof(ret));
    123     if(str[0]=='-') ret.neg=1,mi++;
    124     int len=strlen(str);
    125     ret.len=1;
    126     int cnt=1,pw=1;
    127     for(int i=len-1;i>=mi;i--)
    128     {   
    129         if(cnt==5) 
    130             cnt=1,pw=1,ret.len++;
    131         ret.a[ret.len]+=idx(str[i])*pw;
    132         cnt++,pw*=10;
    133     }
    134     return ret;
    135 }
    136 
    137 int main()
    138 {
    139     scanf("%d",&n);
    140     bignum ret,a,b;
    141     int res,val;
    142     if(n==1){
    143         a=read(),b=read();
    144         ret=a+b;
    145     }else if(n==2){
    146         a=read(),b=read();
    147         ret=a-b;
    148     }else if(n==3){
    149         a=read(),b=read();
    150         ret=a*b;
    151     }else{
    152         a=read();
    153         scanf("%d",&val);
    154         ret=a/val;
    155     }
    156     if(ret.neg)
    157         printf("-");
    158     printf("%d",ret.a[ret.len]);
    159     for(int i=ret.len-1;i>=1;i--)
    160         printf("%04d",ret.a[i]);
    161     puts("");
    162     if(n==4) printf("%d
    ",ret.res);
    163     return 0;
    164 }
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  • 原文地址:https://www.cnblogs.com/guapisolo/p/9920539.html
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