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  • matplotlib双y周实例e

    import pandas as pd
    import numpy as np
    import matplotlib.pyplot as plt
    import pymysql
    import warnings
    import random

    warnings.filterwarnings("ignore")


    def read_db(path):
    close = pd.read_csv(path)
    info = close[:-6]
    zhi_list = []
    for x in info['qx_zu'][20:]:
    x_index = info[info['qx_zu'] == x].index
    all_shuju = info[x_index[0] - 20:x_index[0] - 1]
    zhi = np.mean(all_shuju['qx_zu']) - 2 * (np.std(all_shuju['qx_zu']))
    info[21:]['cha'] = zhi
    zhi_list.append(zhi)
    info['cha'] = 0
    info['cha'][20:] = np.array(zhi_list)

    info['jieguo'] = info['qx_zu'] < info['cha']
    info['jieguo'][:20] = 0
    x_true_index = info[info['jieguo'] == True].index
    x_false_index = info[info['jieguo'] == False].index
    x_small = info.loc[x_true_index]
    x_small['jieguo'] = x_small['close']
    # x_small['jieguo'] = 1
    x_big = info.loc[x_false_index]
    x_big['jieguo'] = 0
    info_all = x_big.append(x_small)
    info_all = info_all.sort_index()
    # print(list(info_all['jieguo']))
    # info_all.to_csv('info_all.csv')
    info_all['date'] = pd.to_datetime(info_all['date'], format='%Y/%m/%d')
    print(info_all['date'])
    return info_all


    def show_info(info):
    """
    画图展示
    :param info:
    :return:
    """

    plt.rcParams['font.sans-serif'] = ['SimHei'] # 设置全局显示汉子
    plt.tick_params(axis='x', labelsize=10) # 设置x轴标签大小
    plt.plot(info['date'], info['close'], 'black')
    plt.legend(loc=4)

    plt.xlabel('时间') # 设置x轴标题

    plt.ylabel('沪深300收盘价', color='black') # 设置Y1轴标题
    # plt.xticks(rotation=110) # 设置时间标签显示格式
    plt.twinx() # 添加一条Y轴,
    plt.axis('off') #不显示刻度
    plt.ylabel('预警信号', color='r') # 设置Y2轴标题

    plt.bar(info['date'], info['jieguo'], label='预警信号', color='r')

    plt.legend(loc='upper right') # 右上
    # 保存图片
    # plt.savefig('image/{}.png'.format('沪深300收盘价'))
    plt.show()


    if __name__ == '__main__':
    show_info(info=read_db('h300_close.csv'))
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  • 原文地址:https://www.cnblogs.com/guofeng-1016/p/12065811.html
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