Given a pattern
and a string str
, find if str
follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern
and a non-empty word in str
.
Examples:
- pattern =
"abba"
, str ="dog cat cat dog"
should return true. - pattern =
"abba"
, str ="dog cat cat fish"
should return false. - pattern =
"aaaa"
, str ="dog cat cat dog"
should return false. - pattern =
"abba"
, str ="dog dog dog dog"
should return false.
Notes:
You may assume pattern
contains only lowercase letters, and str
contains lowercase letters separated by a single space.
Credits:
Special thanks to @minglotus6 for adding this problem and creating all test cases.
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1 public class Solution { 2 public boolean wordPattern(String pattern, String str) { 3 HashMap<Character, String> hm = new HashMap<Character, String>(); 4 Set<String> set = new HashSet<String>(); 5 String[] arr = str.split(" "); 6 if(arr.length != pattern.length()) return false; 7 for(int i =0 ;i< pattern.length();i++){ 8 if(hm.get(pattern.charAt(i)) != null){ 9 if(!hm.get(pattern.charAt(i)).equals(arr[i])) return false; 10 }else{ 11 if(set.contains(arr[i])) return false; 12 else{ 13 hm.put(pattern.charAt(i),arr[i]); 14 set.add(arr[i]); 15 } 16 } 17 } 18 return true; 19 20 } 21 }