Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/"
, => "/home"
path = "/a/./b/../../c/"
, => "/c"
Corner Cases:
- Did you consider the case where path =
"/../"
?
In this case, you should return"/"
. - Another corner case is the path might contain multiple slashes
'/'
together, such as"/home//foo/"
.
In this case, you should ignore redundant slashes and return"/home/foo"
.
1 public class Solution { 2 public String simplifyPath(String path) { 3 StringBuilder ans = new StringBuilder(); 4 LinkedList<String> s = new LinkedList<String>(); 5 String[] tmp = path.split("/"); 6 7 for(String str : tmp){ 8 if("".equals(str) || ".".equals(str)) continue; 9 else if("..".equals(str)){ 10 if(!s.isEmpty()) s.pop(); 11 }else 12 s.push(str); 13 } 14 if(s.isEmpty()) return "/"; 15 while(!s.isEmpty()) ans.append("/"+s.removeLast()); 16 return ans.toString(); 17 } 18 }
该题按照提示,将各种情况考虑一下,比较轻松AC。