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  • 15. 3Sum java solutions

    Given an array S of n integers, are there elements abc in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.

    Note: The solution set must not contain duplicate triplets.

    For example, given array S = [-1, 0, 1, 2, -1, -4],
    
    A solution set is:
    [
      [-1, 0, 1],
      [-1, -1, 2]
    ]

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     1 public class Solution {
     2     List<List<Integer>> ans = new ArrayList<List<Integer>>();
     3     public List<List<Integer>> threeSum(int[] nums) {
     4         if(nums == null || nums.length < 3) return ans;
     5         Arrays.sort(nums);
     6         for(int i = 0; i < nums.length - 2; i++){
     7             if(i > 0 && nums[i] == nums[i-1]) continue;
     8             find3sum(i+1,nums.length-1,nums,0-nums[i]);
     9         }
    10         return ans;
    11     }
    12     
    13     public void find3sum(int s,int e,int[] nums,int target){
    14         while(s < e){
    15             int sum = nums[s] + nums[e];
    16             if(sum == target){
    17                 List<Integer> tmp = new ArrayList<Integer>();
    18                 tmp.add(0-target);
    19                 tmp.add(nums[s++]);
    20                 tmp.add(nums[e--]);
    21                 ans.add(tmp);
    22                 while(s < nums.length-1 && nums[s] == nums[s-1])s++;
    23                 while(e >= 0 && nums[e] == nums[e+1])e--;
    24             }else if(sum < target) s++;
    25             else e--;
    26         }
    27     }
    28 }

    使用求解2sum 的方式来做,要注意的是重复元素的处理。先排序,然后略过重复元素

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  • 原文地址:https://www.cnblogs.com/guoguolan/p/5650907.html
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