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  • 数数字(Digit Counting,ACM/ICPC Danang 2007,UVa1225)

    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    int main()
    {
    char s[10000];
    int a0 = 0, a1 = 0, a2 = 0, a3 = 0, a4 = 0, a5 = 0, a6 = 0, a7 = 0, a8 = 0, a9 = 0;
    scanf("%s", s);
    for (int i = 0; i < strlen(s); i++)
    {
    if (s[i] == '0') a0++;
    if (s[i] == '1') a1++;
    if (s[i] == '2') a2++;
    if (s[i] == '3') a3++;
    if (s[i] == '4') a4++;
    if (s[i] == '5') a5++;
    if (s[i] == '6') a6++;
    if (s[i] == '7') a7++;
    if (s[i] == '8') a8++;
    if (s[i] == '9') a9++;
    }
    printf("%d %d %d %d %d %d %d %d %d %d ", a0, a1, a2, a3, a4, a5, a6, a7, a8, a9);
    system("pause");
    }

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  • 原文地址:https://www.cnblogs.com/guohaoyu110/p/5723126.html
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