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  • Currency Exchange(POJ1860 判正环)

    ~题目链接~

    http://poj.org/problem?id=1860

    Sample Input

    3 2 1 20.0
    1 2 1.00 1.00 1.00 1.00
    2 3 1.10 1.00 1.10 1.00
    

    Sample Output

    YES

    1.Spfa

     1 #include<stdio.h>
     2 #include<string.h>
     3 #include<stdlib.h>
     4 #include<queue>
     5 #define maxn 2<<28
     6 #define maxm 1000+10
     7 
     8 using namespace std;
     9 
    10 struct node
    11 {
    12     double x,y;
    13 } map[maxm][maxm];
    14 
    15 double dis[maxm];
    16 queue<int>Q;
    17 
    18 int Spfa(int n,int s,double k)
    19 {
    20     while(!Q.empty())
    21         Q.pop();
    22     int flag[maxm],i;
    23     memset(flag,0,sizeof(flag));
    24     for(i=1; i<=n; i++)
    25         dis[i]=maxn;
    26     Q.push(s);
    27     dis[s]=k;
    28     flag[s]=1;
    29     while(!Q.empty())
    30     {
    31         int h=Q.front();
    32         Q.pop();
    33         flag[h]=0;
    34         for(i=1; i<=n; i++)
    35             if(dis[i]<(dis[h]-map[h][i].y)*map[h][i].x)//松弛
    36             {
    37                 dis[i]=(dis[h]-map[h][i].y)*map[h][i].x;
    38                 if(!flag[i])
    39                 {
    40                     Q.push(i);
    41                     flag[i]=1;
    42                 }
    43             }
    44         if(dis[s]>k)//判断是否存在正环
    45             return 1;
    46     }
    47     return 0;
    48 }
    49 
    50 int main()
    51 {
    52     int n,m,s,a,b,i;
    53     double k,u,v,w,z;
    54     while(~scanf("%d%d%d%lf",&n,&m,&s,&k))
    55     {
    56         for(i=0; i<m; i++)
    57         {
    58             scanf("%d%d%lf%lf%lf%lf",&a,&b,&u,&v,&w,&z);
    59             map[a][b].x=u;
    60             map[a][b].y=v;
    61             map[b][a].x=w;
    62             map[b][a].y=z;
    63         }
    64         if(Spfa(n,s,k))
    65             printf("YES
    ");
    66         else
    67             printf("NO
    ");
    68     }
    69     return 0;
    70 }
    View Code

    2.Bellman_ford

     1 #include<stdio.h>
     2 #include<string.h>
     3 #include<stdlib.h>
     4 #define maxm 1000+10
     5 
     6 struct node
     7 {
     8     int u,v;
     9     double x,y;
    10 } map[maxm];
    11 
    12 double dis[maxm];
    13 int num;
    14 
    15 int Bellman_ford(int n,int s,double k)
    16 {
    17     int i,j,flag;
    18     memset(dis,0,sizeof(dis));
    19     dis[s]=k;
    20     for(i=0; i<n; i++)
    21     {
    22         flag=0;
    23         for(j=1; j<=num; j++)
    24             if(dis[map[j].v]<(dis[map[j].u]-map[j].y)*map[j].x)
    25             {
    26                 dis[map[j].v]=(dis[map[j].u]-map[j].y)*map[j].x;
    27                 flag=1;
    28             }
    29         if(!flag)
    30             break;
    31     }
    32     if(i>=n)//判断松弛后,是否存在正环
    33         return 1;
    34     return 0;
    35 }
    36 
    37 int main()
    38 {
    39     int n,m,s,a,b,i;
    40     double k,u,v,w,z;
    41     while(~scanf("%d%d%d%lf",&n,&m,&s,&k))
    42     {
    43         num=0;
    44         for(i=0; i<m; i++)
    45         {
    46             scanf("%d%d%lf%lf%lf%lf",&a,&b,&u,&v,&w,&z);
    47             map[++num]=((struct node){a,b,u,v});
    48             map[++num]=((struct node){b,a,w,z});
    49         }
    50         if(Bellman_ford(n,s,k))
    51             printf("YES
    ");
    52         else
    53             printf("NO
    ");
    54     }
    55     return 0;
    56 }
    View Code
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  • 原文地址:https://www.cnblogs.com/guoyongzhi/p/3258883.html
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