56、获取所有员工的emp_no

1、题目描述

获取所有员工的emp_no、部门编号dept_no以及对应的bonus类型btype和received ，没有分配具体的员工不显示
CREATE TABLE `dept_emp` ( `emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,

PRIMARY KEY (`emp_no`,`from_date`));

create table emp_bonus(
emp_no int not null,
recevied datetime not null,
btype smallint not null);

输出格式:

e.emp_no	dept_no	btype	received
10001	d001	1	2010-01-01
10002	d001	2	2010-10-01
10003	d004	3	2011-12-03
10004	d004	1	2010-01-01
10005	d003
10006	d002
10007	d005
10008	d005
10009	d006
10010	d005
10010	d006

2、代码

select de.emp_no,de.dept_no,eb.btype,eb.recevied 
from dept_emp de 
left join emp_bonus eb on de.emp_no=eb.emp_no;