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  • ZigZag Conversion [LeetCode]

     

    The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

    P   A   H   N
    A P L S I I G
    Y   I   R
    
    And then read line by line: "PAHNAPLSIIGYIR"

    Write the code that will take a string and make this conversion given a number of rows:

    string convert(string text, int nRows);
    convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

    Summary: just finds the index in string s of every rows.

     1     string convert(string s, int nRows) {
     2         string output;
     3         if(nRows <= 0)
     4             return output;
     5         if(nRows == 1 || nRows == s.size())
     6             return s;
     7             
     8         for(int i = 0; i < nRows; i ++) {
     9             if(i == 0 || i + 1 == nRows){
    10                 int j = i;
    11                 while(j < s.size()){
    12                     output += s[j];
    13                     j += nRows + nRows - 2;
    14                 }
    15             }else{
    16                 int j = 0 + i;
    17                 while(j < s.size()){
    18                     output += s[j];
    19                     int next_idx = j + nRows - (i + 1) + nRows - (i + 1);
    20                     if(next_idx < s.size())
    21                         output += s[next_idx];
    22                     j += nRows + nRows - 2;
    23                 }
    24             }                                                                                                                                                                                                                               
    25         }
    26         return output;
    27     }
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  • 原文地址:https://www.cnblogs.com/guyufei/p/3412336.html
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