Given a set of distinct integers, S, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If S = [1,2,3]
, a solution is:
[ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ]
Summary: Recursive approach, we can optimize it.
1 vector<vector<int> > subsets(vector<int> &S) { 2 std::sort(S.begin(), S.end()); 3 vector<vector<int> > result; 4 vector<int> subset; 5 result.push_back(subset); 6 if(S.size() == 0) 7 return result; 8 for(int i = 0; i < S.size(); i ++) { 9 vector<int> sub_s(S.begin() + i + 1, S.end()); 10 vector<vector<int> > ret = subsets(sub_s); 11 for(auto item : ret){ 12 item.insert(item.begin(), S[i]); 13 result.push_back(item); 14 } 15 } 16 17 return result; 18 }