Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[ [2], [3,4], [6,5,7], [4,1,8,3] ]
The minimum path sum from top to bottom is 11
(i.e., 2 + 3 + 5 + 1 = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
Approach #1: DP.[C++]
class Solution { public: int minimumTotal(vector<vector<int>>& triangle) { for (int i = triangle.size()-2; i >= 0; --i) for (int j = 0; j <= i; ++j) triangle[i][j] += min(triangle[i+1][j], triangle[i+1][j+1]); return triangle[0][0]; } };