This time, you are supposed to find A+B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:
K N1 aN1 N2 aN2 ... NK aNK
where K is the number of nonzero terms in the polynomial, Ni and aNi (,) are the exponents and coefficients, respectively. It is given that 1,0.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input:
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output:
3 2 1.5 1 2.9 0 3.2
题解:用C++写了两次只通过了部分数据额,最后看别人的博客是用C语言来写的,确实,用C++来控制输入输出的格式不太好控制。
#include<iostream> using namespace std; int main() { float a[1001] = {0}; int k; int exp; float coe; cin >> k; for(int i = 0; i < k; ++i) { cin >> exp >> coe; a[exp] += coe; } cin >> k; for(int i = 0; i < k; ++i) { cin >> exp >> coe; a[exp] += coe; } int count = 0; for (int i = 0; i < 1001; ++i) { if (a[i] != 0) count++; } cout << count; for (int i = 1000; i >= 0; --i) { if (a[i] > 0) cout << " " << i << " " << a[i]; } }
2021-01-28
Python列表表达式:[ expression for i in iterable ]
poly = [0 for _ in range(1001)]按照习惯,有时候单个独立下划线是用作一个名字,来表示某个变量是临时的或无关紧要的。
例如,在下面的循环中,我们不需要访问正在运行的索引,我们可以使用“_”来表示它只是一个临时值
poly = [0 for _ in range(1001)] def add(): global poly line = input().split()[1:] i = 0 while i < len(line) - 1: poly[int(line[i])] += float(line[i + 1]) i += 2 add() add() count = 0 for i in range(1000, -1, -1): if poly[i] != 0: count += 1 print(count, end='') for i in range(1000, -1, -1): if poly[i] != 0: print(" %d %.1f" % (i, poly[i]), end='')