Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
Input: "Hello World" Output: 5
AC code:
class Solution {
public:
int lengthOfLastWord(string s) {
int tail = s.length() - 1;
int len = 0;
while (tail >= 0 && s[tail] == ' ') tail--;
while (tail >= 0 && s[tail--] != ' ') len++;
return len;
}
};
Runtime: 0 ms, faster than 100.00% of C++ online submissions for Length of Last Word.