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  • 61. Rotate List

    Given a linked list, rotate the list to the right by k places, where k is non-negative.

    Example 1:

    Input: 1->2->3->4->5->NULL, k = 2
    Output: 4->5->1->2->3->NULL
    Explanation:
    rotate 1 steps to the right: 5->1->2->3->4->NULL
    rotate 2 steps to the right: 4->5->1->2->3->NULL
    

    Example 2:

    Input: 0->1->2->NULL, k = 4
    Output: 2->0->1->NULL
    Explanation:
    rotate 1 steps to the right: 2->0->1->NULL
    rotate 2 steps to the right: 1->2->0->NULL
    rotate 3 steps to the right: 0->1->2->NULL
    rotate 4 steps to the right: 2->0->1->NULL
    AC code:
    /**
     * Definition for singly-linked list.
     * struct ListNode {
     *     int val;
     *     ListNode *next;
     *     ListNode(int x) : val(x), next(NULL) {}
     * };
     */
    class Solution {
    public:
        ListNode* rotateRight(ListNode* head, int k) {
            if (!head) return NULL;
            ListNode* newN;
            ListNode* tail;
            newN = tail = head;
            int len = 1;
            while (tail->next) {
                tail = tail->next;
                len++;
            }
            tail->next = head;
            if (k %= len) {
                for (int i = 0; i < len - k; ++i) {
                    tail = tail->next;
                }
            }
            newN = tail->next;
            tail->next = NULL;
            return newN;
        }
    };
    

      

     
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  • 原文地址:https://www.cnblogs.com/h-hkai/p/9823063.html
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