zoukankan      html  css  js  c++  java
  • P2590 [ZJOI2008]树的统计

    的确是入门题

    #include<bits/stdc++.h>
    #define N 100005
    #define inf 1000000000
    using namespace std;
    int n,q,a[4*N];
    struct Edge{
        int u,v,next;
    }G[N];
    int tot=0,head[N];
    int size[100005],wson[100005],fa[100005],d[100005],top[100005];
    int tpos[100005],pre[100005],cnt=0;
    inline void addedge(int u,int v){
        G[++tot].u=u;G[tot].v=v;G[tot].next=head[u];head[u]=tot;
        G[++tot].u=v;G[tot].v=u;G[tot].next=head[v];head[v]=tot;
    }
    void dfs1(int u,int f){
        size[u]=1;
        for (int i=head[u];i;i=G[i].next){
            int v=G[i].v;if (v==f)continue;
            d[v]=d[u]+1;fa[v]=u;
            dfs1(v,u);
            size[u]+=size[v];
            if (size[v]>size[wson[u]])wson[u]=v;
        }
    }
    void dfs2(int u,int TP){
        tpos[u]=++cnt;pre[cnt]=u;top[u]=TP;
        if (wson[u])dfs2(wson[u],TP);
        for (int i=head[u];i;i=G[i].next){
            int v=G[i].v;
            if (v==fa[u]||v==wson[u])continue;
            dfs2(v,v);
        }
    }
    int sumv[4*N],maxv[4*N];
    inline void pushup(int o){
        sumv[o]=sumv[o*2]+sumv[o*2+1];
        maxv[o]=max(maxv[o*2],maxv[o*2+1]);
    }
    void build(int o,int l,int r){
        int mid=(l+r)/2;
        if (l==r){sumv[o]=maxv[o]=a[pre[l]];return;}
        build(o*2,l,mid);build(o*2+1,mid+1,r);
        pushup(o);
    }
    void update(int o,int l,int r,int q,int v){
        int mid=(l+r)/2;
        if (l==r){sumv[o]=maxv[o]=v;return;}
        if (q<=mid)update(o*2,l,mid,q,v);
        else update(o*2+1,mid+1,r,q,v);
        pushup(o);
    }
    int querysum(int o,int l,int r,int ql,int qr){
        int mid=(l+r)/2,ans=0;
        if (ql<=l&&r<=qr)return sumv[o];
        if (ql<=mid)ans+=querysum(o*2,l,mid,ql,qr);
        if (qr>mid)ans+=querysum(o*2+1,mid+1,r,ql,qr);
        pushup(o);
        return ans;
    }
    int querymax(int o,int l,int r,int ql,int qr){
        int mid=(l+r)/2,ans=-inf;
        if (ql<=l&&r<=qr)return maxv[o];
        if (ql<=mid)ans=max(ans,querymax(o*2,l,mid,ql,qr));
        if (qr>mid)ans=max(ans,querymax(o*2+1,mid+1,r,ql,qr));
        pushup(o);
        return ans;
    }
    int qsum(int u,int v){
        int ans=0;
        while (top[u]!=top[v]){
            if (d[top[u]]<d[top[v]])swap(u,v);
            ans+=querysum(1,1,n,tpos[top[u]],tpos[u]);
            u=fa[top[u]];
        }
        if (d[u]<d[v])swap(u,v);
        ans+=querysum(1,1,n,tpos[v],tpos[u]);
        return ans;
    }
    int qmax(int u,int v){
        int ans=-inf;
        while (top[u]!=top[v]){
            if (d[top[u]]<d[top[v]])swap(u,v);
            ans=max(ans,querymax(1,1,n,tpos[top[u]],tpos[u]));
            u=fa[top[u]];
        }
        if (d[u]<d[v])swap(u,v);
        ans=max(ans,querymax(1,1,n,tpos[v],tpos[u]));
        return ans;
    }
    int main(){
        memset(head,0,sizeof(head));
        memset(a,0,sizeof(a));
        scanf("%d",&n);
        for (int i=1;i<n;i++){
            int u,v;
            scanf("%d%d",&u,&v);
            addedge(u,v);
        }
        for (int i=1;i<=n;i++)scanf("%d",&a[i]);
        d[1]=1;fa[1]=1;dfs1(1,-1);dfs2(1,1);build(1,1,n);
        scanf("%d",&q);
        while (q--){
            int x,y;
            char s[10];
            scanf("%s%d%d",s,&x,&y);
            if (s[1]=='H')update(1,1,n,tpos[x],y);
            if (s[1]=='M')printf("%d
    ",qmax(x,y));
            if (s[1]=='S')printf("%d
    ",qsum(x,y));
        }
        return 0;
    }
    

      

  • 相关阅读:
    Java调度实现
    关于《报表》的实际运用案例
    mybaits错误解决:There is no getter for property named 'parentId ' in class 'java.lang.String'
    Java Eclipse进行断点调试
    切割时间工具类
    JavaWeb开发技术基础概念回顾篇
    解决无线网络连接出现黄色感叹号---win10
    登录界面Demo
    MD5加密Demo
    java.lang.NullPointerException&com.cb.action.LoginAction.execute(LoginAction.java:48)
  • 原文地址:https://www.cnblogs.com/hahaha2124652975/p/11231069.html
Copyright © 2011-2022 走看看