sql语句:
select a.id,substring_index(substring_index(a.name,',',b.help_topic_id+1),',',-1) name from test a join mysql.help_topic b on b.help_topic_id < (length(a.name) - length(replace(a.name,',',''))+1) order by a.id;
结果:
转载:https://blog.csdn.net/qq_34542964/article/details/72821764