Semaphore为并发包中提供用于控制某资源同时可以被几个线程访问的类
实例代码:
// 允许2个线程同时访问
final Semaphore semaphore = new Semaphore(2);
ExecutorService executorService = Executors.newCachedThreadPool();
for (int i = 0; i < 10; i++) {
final int index = i;
executorService.execute(new Runnable() {
public void run() {
try {
semaphore.acquire();
// 这里可能是业务代码
System.out.println("线程:" + Thread.currentThread()。getName() + "获得许可:" + index);
TimeUnit.SECONDS.sleep(1);
semaphore.release();
System.out.println("允许TASK个数:" + semaphore.availablePermits());
} catch (InterruptedException e) {
e.printStackTrace();
}
}
});
}
executorService.shutdown();
构造方法1:
public Semaphore(int permits) {
sync = new NonfairSync(permits);
}
permits 初始许可数,也就是最大访问线程数
构造方法2:
public Semaphore(int permits, boolean fair) {
sync = (fair)? new FairSync(permits) : new NonfairSync(permits);
}
permits 初始许可数,也就是最大访问线程数
fair 当设置为false时,线程获取许可的顺序是无序的,也就是说新线程可能会比等待的老线程会先获得许可;当设置为true时,信号量保证它们调用的顺序(即先进先出;FIFO)
主要方法:托福答案 www.yztrans.com
void acquire() 从信号量获取一个许可,如果无可用许可前 将一直阻塞等待,
void acquire(int permits) 获取指定数目的许可,如果无可用许可前 也将会一直阻塞等待
boolean tryAcquire() 从信号量尝试获取一个许可,如果无可用许可,直接返回false,不会阻塞
boolean tryAcquire(int permits) 尝试获取指定数目的许可,如果无可用许可直接返回false,
boolean tryAcquire(int permits, long timeout, TimeUnit unit) 在指定的时间内尝试从信号量中获取许可,如果在指定的时间内获取成功,返回true,否则返回false
void release() 释放一个许可,别忘了在finally中使用,注意:多次调用该方法,会使信号量的许可数增加,达到动态扩展的效果,如:初始permits 为1, 调用了两次release,最大许可会改变为2
int availablePermits() 获取当前信号量可用的许可
JDK 非公平Semaphore实现:
1.使用一个参数的构造创建Semaphore对象时,会创建一个NonfairSync对象实例,并将state值设为传入的值(permits ),
public Semaphore(int permits) {
sync = new NonfairSync(permits);
}
NonfairSync间接的继承了AbstractQueuedSynchronizer实现
final static class NonfairSync extends Sync {
private static final long serialVersionUID = -2694183684443567898L;
NonfairSync(int permits) {
super(permits);
}
protected int tryAcquireShared(int acquires) {
return nonfairTryAcquireShared(acquires);
}
}
abstract static class Sync extends AbstractQueuedSynchronizer {
private static final long serialVersionUID = 1192457210091910933L;
Sync(int permits) {
setState(permits);
}
AbstractQueuedSynchronizer 的setState方法
protected final void setState(int newState) {
state = newState;
}
2.调用tryAcquire方法时,实际是调用NonfairSync的nonfairTryAcquireShared方法,nonfairTryAcquireShared在父类Sync中实现,
Semaphore# tryAcquire方法:
public boolean tryAcquire() {
return sync.nonfairTryAcquireShared(1) >= 0;
}
Sync的nonfairTryAcquireShared方法
final int nonfairTryAcquireShared(int acquires) {
for (;;) {
int available = getState();
int remaining = available - acquires;
if (remaining < 0 ||
compareAndSetState(available, remaining))
return remaining;
}
}
nonfairTryAcquireShared方法通过获取当前的state,以此state减去需要获取信号量的个数,作为剩余个数,如果结果小于0,返回此剩余的个数;如果结果大于等于0,则基于CAS将state的值设置为剩余个数,当前步骤用到了for循环,所以只有在结果小于0或设置state值成功的情况下才会退出。
如果返回的剩余许可个数大于0,tryAcquire方法则返回true;其余返回false.托福答案 www.qcwy123.com
AbstractQueuedSynchronizer的compareAndSetState方法,
protected final boolean compareAndSetState(int expect, int update) {
// See below for intrinsics setup to support this
return unsafe.compareAndSwapInt(this, stateOffset, expect, update);
}
3.release方法,释放一个许可
public void release() {
sync.releaseShared(1);
}
AbstractQueuedSynchronizer的releaseShared方法,
public final boolean releaseShared(int arg) {
if (tryReleaseShared(arg)) {
doReleaseShared();
return true;
}
return false;
}
release方法间接的调用了Sync的tryReleaseShared方法,该方法基于Cas 将state的值设置为state+1,一直循环确保CAS操作成功,成功后返回true.
protected final boolean tryReleaseShared(int releases) {
for (;;) {
int p = getState();
if (compareAndSetState(p, p + releases))
return true;
}
}
根据上面分析,可以看得出,Semaphore采用了CAS来实现,尽量避免锁的使用,提高了性能。