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  • convert CAN frame

    前言

    最近了解了一些socket can的知识点,本文主要介绍如何将数据转换为CAN报文,前提是已经确定CAN的传输协议。

    本文使用的CAN报文共有22条,这些报文共用一个can id,每条报文使用序号标志;

    报文协议

    转换数据程序

    char* convert_buf(vector<Point>& probp, vector<Distance>& pdist, vector<int>& plabel)
    {
        //convert-can-frame.
        char buffer[22][8] = { 0 };
        for (int i = 0; i < 22; i++)
        {
            double lat_factor = 0.1;
            double long_factor = 0.2;
    
            unsigned int lat01 = static_cast<unsigned int>(pdist[3 * i].x_dis / lat_factor);//unit-2dm-8bits.
            unsigned int long01 = static_cast<unsigned int>(pdist[3 * i].y_dis / long_factor);//unit-2dm-9bits.
            int label01 = plabel[i*3];
    
            if (i == 21)
            {
                buffer[i][0] = (((i+1) & 0xFF) << 3) + ((long01 & 0x1FF) >> 6);
                buffer[i][1] = ((long01 & 0x1FF) << 2) + ((lat01 & 0xFF) >> 6);
                buffer[i][2] = ((lat01 & 0xFF) << 2) + (label01 & 0x03);
                break;
            }
    
            unsigned int lat02 = static_cast<unsigned int>(pdist[3 * i + 1].x_dis / lat_factor);//unit-2dm-8bits.
            unsigned int long02 = static_cast<unsigned int>(pdist[3 * i + 1].y_dis / long_factor);//unit-2dm-9bits.
            int label02 = plabel[3 * i + 1];
    
            unsigned int lat03 = static_cast<unsigned int>(pdist[3 * i + 2].x_dis / lat_factor);//unit-2dm-8bits.
            unsigned int long03 = static_cast<unsigned int>(pdist[3 * i + 2].y_dis / long_factor);//unit-2dm-9bits.
            int label03 = plabel[3 * i + 2];
    
            std::cout << "long01 --- " << long01 << "-- long02 --- " << long02 << "--- long03 --- " << long03 << std::endl;
            buffer[i][0] = (((i + 1) & 0xFF) << 3) + ((long01 & 0x1FF) >> 6);
            buffer[i][1] = ((long01 & 0x1FF) << 2) + ((lat01 & 0xFF) >> 6);
            buffer[i][2] = ((lat01 & 0xFF) << 2) + (label01 & 0x03);
            buffer[i][3] = ((long02 & 0x1FF) >> 1);
            buffer[i][4] = ((long02 & 0x1FF) << 7) + ((lat02 & 0xFF) >> 1);
            buffer[i][5] = ((lat02 & 0xFF) << 7) + ((label02 & 0x03) << 5) + ((long03 & 0x1FF) >> 4);
            buffer[i][6] = ((long03 & 0x1FF) << 4) + ((lat03 & 0xFF) >> 4);
            buffer[i][7] = ((lat03 & 0xFF) << 4) + ((label03 & 0x03) << 2);
    
            printf("buffer[0]: --- %x
    ", (byte)buffer[i][0]);
            printf("buffer[1]: --- %x
    ", (byte)buffer[i][1]);
            printf("buffer[2]: --- %x
    ", (byte)buffer[i][2]);
            printf("buffer[3]: --- %x
    ", (byte)buffer[i][3]);
            printf("buffer[4]: --- %x
    ", (byte)buffer[i][4]);
            printf("buffer[5]: --- %x
    ", (byte)buffer[i][5]);
            printf("buffer[6]: --- %x
    ", (byte)buffer[i][6]);
            printf("buffer[7]: --- %x
    ", (byte)buffer[i][7]);
    
        }
        cout << "sizeof(buffer): " << sizeof(buffer) << " Byte..." << endl;
        return buffer[0];
    
    }
    View Code

    注意

    1.如何确定CAN协议的格式,特别是信号的范围、精度以及比特位数;

    2.浮点型数据如何变换为可以进行逻辑运算和位移操作的数据类型;

    3.如何按照报文格式得到每个字节的内容,特别是位移操作;

    4.如何将报文内容正确输出方便查看;

    5.原始数据可能越界,应该在转换为报文数据之前对原始数据进行越界处理;

    6.转换为CAN报文过程中的各个操作符号的优先级;

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  • 原文地址:https://www.cnblogs.com/happyamyhope/p/8868619.html
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