zoukankan      html  css  js  c++  java
  • 算法:非平衡二叉搜索树(UnBalanced Binary Search Tree)

    背景

    很多场景下都需要将元素存储到已排序的集合中。用数组来存储,搜索效率非常高: O(log n),但是插入效率比较低:O(n)。用链表来存储,插入效率和搜索效率都比较低:O(n)。如何能提供插入和搜索效率呢?这就是二叉搜索树的由来,本文先介绍非平衡二叉搜索树。

    非平衡二叉搜索树

    规则

    所有节点的左节点小于节点,所有节点的右节点大于等于自身,即:node.value >  node.left.value && node.value <= node.right.value。

    示例

    根据上面的规则,我们也很容易找到最大值和最小值,后面也会用到这种算法。最大值可以通过递归方法 node.right 得到,最小值可以递归 node.left 得到。

    为什么叫非平衡?

    说明:下图变成链表了,这会导致效率非常低,后面找机会再介绍平衡算法。

    实现

    搜索、遍历(前序、中序和后序)、添加算法都比较简单,可以直接看后面的代码,这里重点介绍一下删除算法。

    如何删除元素?

    第一步:要找到删除的元素(current)。

    第二步:判断 current 满足如下哪种场景:

    1. current.Right == null
      示例

      代码
       1                     if (parent == null)
       2                     {
       3                         this.Root = current.Left;
       4                     }
       5                     else if (isLeft)
       6                     {
       7                         parent.Left = current.Left;
       8                     }
       9                     else
      10                     {
      11                         parent.Right = current.Left;
      12                     }

      结果

    2. current.Right != null && current.Right.Left == null
      示例

      代码
       1                     current.Right.Left = current.Left;
       2 
       3                     if (parent == null)
       4                     {
       5                         this.Root = current.Right;
       6                     }
       7                     else if (isLeft)
       8                     {
       9                         parent.Left = current.Right;
      10                     }
      11                     else
      12                     {
      13                         parent.Right = current.Right;
      14                     }

      结果

    3. current.Right != null && current.Right.Left != null
      示例

      代码
       1                     Node<T> currentRightSmallestParent = current.Right;
       2                     var currentRightSmallest = current.Right.Left;
       3 
       4                     this.FindSmallest(ref currentRightSmallestParent, ref currentRightSmallest);
       5 
       6                     currentRightSmallestParent.Left = currentRightSmallest.Right;
       7                     currentRightSmallest.Left = current.Left;
       8                     currentRightSmallest.Right = current.Right;
       9                     if (parent == null)
      10                     {
      11                         this.Root = currentRightSmallest;
      12                     }
      13                     else if (isLeft)
      14                     {
      15                         parent.Left = currentRightSmallest;
      16                     }
      17                     else
      18                     {
      19                         parent.Right = currentRightSmallest;
      20                     }

      结果

      说明
      这里的重点是 FindSmallest,找出 current.Right.Left 子树中最小的元素,然后用它替换 current。

    完整代码

      1 using System;
      2 using System.Collections.Generic;
      3 using System.Linq;
      4 using System.Text;
      5 using System.Threading.Tasks;
      6 
      7 namespace DataStuctureStudy.Trees
      8 {
      9     class UnBalancedBinarySearchTree
     10     {
     11         class Node<T>
     12             where T : IComparable<T>
     13         {
     14             public T Value { get; set; }
     15 
     16             public Node<T> Left { get; set; }
     17 
     18             public Node<T> Right { get; set; }
     19 
     20             public void InOrderTraverse(Action<T> action)
     21             {
     22                 if (this.Left != null)
     23                 {
     24                     this.Left.InOrderTraverse(action);
     25                 }
     26 
     27                 action(this.Value);
     28 
     29                 if (this.Right != null)
     30                 {
     31                     this.Right.InOrderTraverse(action);
     32                 }
     33             }
     34 
     35             public int Depth()
     36             {
     37                 var leftDepth = 0;
     38                 var rightDepth = 0;
     39 
     40                 if (this.Left != null)
     41                 {
     42                     leftDepth = this.Left.Depth();
     43                 }
     44                 if (this.Right != null)
     45                 {
     46                     rightDepth = this.Right.Depth();
     47                 }
     48 
     49                 return
     50                     leftDepth > rightDepth
     51                     ? leftDepth + 1
     52                     : rightDepth + 1;
     53             }
     54         }
     55 
     56         public class Tree<T>
     57              where T : IComparable<T>
     58         {
     59             private Node<T> Root { get; set; }
     60 
     61             public void Display()
     62             {
     63                 Console.WriteLine();
     64 
     65                 if (this.Root == null)
     66                 {
     67                     return;
     68                 }
     69 
     70                 var depth = this.Root.Depth();
     71                 var buffers = new string[depth][];
     72                 for (int i = 0; i < buffers.Length; i++)
     73                 {
     74                     buffers[i] = new string[(int)(Math.Pow(2, depth) - 1)];
     75                 }
     76 
     77                 this.BuildArray(this.Root, depth, buffers, 0, 0);
     78 
     79                 for (int i = 0; i < buffers.Length; i++)
     80                 {
     81                     for (int j = 0; j < buffers[i].Length; j++)
     82                     {
     83                         if (buffers[i][j] == null)
     84                         {
     85                             Console.Write(new string(' ', 5));
     86                         }
     87                         else
     88                         {
     89                             var leftPad = (5 - buffers[i][j].Length) / 2;
     90                             Console.Write(buffers[i][j]
     91                                 .PadLeft(leftPad + buffers[i][j].Length)
     92                                 .PadRight(5));
     93                         }
     94                     }
     95                     Console.WriteLine();
     96                     Console.WriteLine();
     97                 }
     98             }
     99 
    100             private void BuildArray(Node<T> node, int nodeDepth, string[][] buffers, int row, int startColumn)
    101             {
    102                 if (node == null)
    103                 {
    104                     return;
    105                 }
    106 
    107                 var nodeWidth = Math.Pow(2, nodeDepth) - 1;
    108                 var column = (int)(startColumn + nodeWidth / 2);
    109 
    110                 buffers[row][column] = node.Value.ToString();
    111 
    112                 this.BuildArray(node.Left, nodeDepth - 1, buffers, row + 1, startColumn);
    113                 this.BuildArray(node.Right, nodeDepth - 1, buffers, row + 1, column + 1);
    114             }
    115 
    116             public bool Contains(T item)
    117             {
    118                 var current = this.Root;
    119 
    120                 while (current != null)
    121                 {
    122                     if (item.CompareTo(current.Value) == 0)
    123                     {
    124                         return true;
    125                     }
    126                     else if (item.CompareTo(current.Value) < 0)
    127                     {
    128                         current = current.Left;
    129                     }
    130                     else
    131                     {
    132                         current = current.Right;
    133                     }
    134                 }
    135 
    136                 return false;
    137             }
    138 
    139             public void InOrderTraverse(Action<T> action)
    140             {
    141                 if (this.Root != null)
    142                 {
    143                     this.Root.InOrderTraverse(action);
    144                 }
    145             }
    146 
    147             public void Insert(T item)
    148             {
    149                 var node = new Node<T> { Value = item };
    150 
    151                 Node<T> parent = null;
    152                 var current = this.Root;
    153                 var isLeft = false;
    154 
    155                 while (current != null)
    156                 {
    157                     parent = current;
    158 
    159                     if (item.CompareTo(current.Value) < 0)
    160                     {
    161                         current = current.Left;
    162                         isLeft = true;
    163                     }
    164                     else
    165                     {
    166                         current = current.Right;
    167                         isLeft = false;
    168                     }
    169                 }
    170 
    171                 if (parent == null)
    172                 {
    173                     this.Root = node;
    174                 }
    175                 else if (isLeft)
    176                 {
    177                     parent.Left = node;
    178                 }
    179                 else
    180                 {
    181                     parent.Right = node;
    182                 }
    183             }
    184 
    185             public bool Delete(T item)
    186             {
    187                 Node<T> parent = null;
    188                 var current = this.Root;
    189                 var isLeft = false;
    190 
    191                 this.Find(item, ref parent, ref current, ref isLeft);
    192 
    193                 if (current == null)
    194                 {
    195                     return false;
    196                 }
    197 
    198                 if (current.Right == null)
    199                 {
    200                     if (parent == null)
    201                     {
    202                         this.Root = current.Left;
    203                     }
    204                     else if (isLeft)
    205                     {
    206                         parent.Left = current.Left;
    207                     }
    208                     else
    209                     {
    210                         parent.Right = current.Left;
    211                     }
    212                 }
    213                 else if (current.Right != null && current.Right.Left == null)
    214                 {
    215                     current.Right.Left = current.Left;
    216 
    217                     if (parent == null)
    218                     {
    219                         this.Root = current.Right;
    220                     }
    221                     else if (isLeft)
    222                     {
    223                         parent.Left = current.Right;
    224                     }
    225                     else
    226                     {
    227                         parent.Right = current.Right;
    228                     }
    229                 }
    230                 else
    231                 {
    232                     Node<T> currentRightSmallestParent = current.Right;
    233                     var currentRightSmallest = current.Right.Left;
    234 
    235                     this.FindSmallest(ref currentRightSmallestParent, ref currentRightSmallest);
    236 
    237                     currentRightSmallestParent.Left = currentRightSmallest.Right;
    238                     currentRightSmallest.Left = current.Left;
    239                     currentRightSmallest.Right = current.Right;
    240                     if (parent == null)
    241                     {
    242                         this.Root = currentRightSmallest;
    243                     }
    244                     else if (isLeft)
    245                     {
    246                         parent.Left = currentRightSmallest;
    247                     }
    248                     else
    249                     {
    250                         parent.Right = currentRightSmallest;
    251                     }
    252                 }
    253 
    254                 return true;
    255             }
    256 
    257             private void Find(T item, ref Node<T> parent, ref Node<T> current, ref bool isLeft)
    258             {
    259                 while (current != null)
    260                 {
    261                     if (item.CompareTo(current.Value) == 0)
    262                     {
    263                         break;
    264                     }
    265 
    266                     parent = current;
    267 
    268                     if (item.CompareTo(current.Value) < 0)
    269                     {
    270                         current = current.Left;
    271                         isLeft = true;
    272                     }
    273                     else
    274                     {
    275                         current = current.Right;
    276                         isLeft = false;
    277                     }
    278                 }
    279             }
    280 
    281             private void FindSmallest(ref Node<T> parent, ref Node<T> current)
    282             {
    283                 while (current != null)
    284                 {
    285                     if (current.Left == null)
    286                     {
    287                         break;
    288                     }
    289 
    290                     parent = current;
    291                     current = current.Left;
    292                 }
    293             }
    294         }
    295     }
    296 }

    备注

    学完这个树的最大收获就是,找到了一种输出树形结构相对高效的方法,比我之前用的高效,这种算法可以用在组织结构图的生成中。

  • 相关阅读:
    九章算术卷第二 粟米
    九章算术卷第一 方田
    九章算术卷第一 方田
    九章算术 原序
    软件开发活动
    软件开发活动
    趣味程序之数学之美系列
    I00019 生成全8数
    Sagheer and Nubian Market CodeForces
    Codeforces Round #533 (Div. 2) A. Salem and Sticks(暴力)
  • 原文地址:https://www.cnblogs.com/happyframework/p/3489148.html
Copyright © 2011-2022 走看看