zoukankan      html  css  js  c++  java
  • thread互斥测试

    thread互斥测试

    编译运行附件中的代码,并说明程序的功能
    根据自己的理解,提交不少于3张图片

    代码

    #include  <stdio.h>
    #include  <stdlib.h>
    #include  <pthread.h>
    #include  <ctype.h>
     
    struct arg_set {
            char *fname;
            int  count;
    };
     
    struct arg_set  *mailbox = NULL;
    pthread_mutex_t lock = PTHREAD_MUTEX_INITIALIZER;//互斥锁
    pthread_cond_t  flag = PTHREAD_COND_INITIALIZER;//条件变量
     
    void *count_words(void *);
    int main(int argc, char *argv[])
    {
        pthread_t t1, t2;
        struct arg_set args1, args2;   
        int reports_in = 0;
        int total_words = 0;
     
        if ( argc != 3 ){
            printf("usage: %s file1 file2\n", argv[0]);
            exit(1);
        }
     
        args1.fname = argv[1];
        args1.count = 0;
        pthread_create(&t1, NULL, count_words, (void *) &args1);
     
        args2.fname = argv[2];
        args2.count = 0;
        pthread_create(&t2, NULL, count_words, (void *) &args2);
     
        pthread_mutex_lock(&lock);//拿到互斥锁,进入临界区
        while( reports_in < 2 ){
            printf("MAIN: waiting for flag to go up\n");
            pthread_cond_wait(&flag, &lock); //令线程等待在条件变量上
            printf("MAIN: Wow! flag was raised, I have the lock\n");
            printf("%7d: %s\n", mailbox->count, mailbox->fname);
            total_words += mailbox->count;
            if ( mailbox == &args1)
                pthread_join(t1,NULL);//等待线程t1执行结束
            if ( mailbox == &args2)
                pthread_join(t2,NULL);//等待线程t2执行结束
            mailbox = NULL;
            pthread_cond_signal(&flag); //通知等待在条件变量上的线程
            reports_in++;
        }
        pthread_mutex_unlock(&lock);//释放互斥锁
         
        printf("%7d: total words\n", total_words);
    }
    void *count_words(void *a)
    {
        struct arg_set *args = a;
        FILE *fp;
        int  c, prevc = '\0';
         
        if ( (fp = fopen(args->fname, "r")) != NULL ){
            while( ( c = getc(fp)) != EOF ){
                if ( !isalnum(c) && isalnum(prevc) )
                    args->count++;
                prevc = c;
            }
            fclose(fp);
        } else
            perror(args->fname);
        printf("COUNT: waiting to get lock\n");
        pthread_mutex_lock(&lock);//拿到互斥锁,进入临界区
        printf("COUNT: have lock, storing data\n");
        if ( mailbox != NULL ){
            printf("COUNT: oops..mailbox not empty. wait for signal\n");
            pthread_cond_wait(&flag,&lock);
        }
        mailbox = args;        
        printf("COUNT: raising flag\n");
        pthread_cond_signal(&flag); //通知等在条件变量上的线程
        printf("COUNT: unlocking box\n");
        pthread_mutex_unlock(&lock);   
        return NULL;
    }
    

    运行结果

  • 相关阅读:
    python 继承与组合
    google浏览器安装不上的绝望经历
    python 类,对象
    Javascript学习笔记——闭包
    面试小结:html/css实现元素居中
    @清晰掉 qsort()
    @清晰掉 sprintf sscanf双胞胎
    @清晰掉 GDB调试器中的战斗机
    @大脑练习: 计算两个矩阵的乘积
    js测试用
  • 原文地址:https://www.cnblogs.com/harperhjl/p/15555138.html
Copyright © 2011-2022 走看看