【PAT】B1002 写出这个数

思路：
1.以字符串形式输入数据，计算结果
2.使用sprintf将结果数字转换为字符串（将数字每一位分开）
3.分别输出字符每一位

1，笨方法，用的ifelse来判断输出

#include<stdio.h>
#include<string.h>
char arr[110];

int getsum() {
	int sum = 0;
	int len = strlen(arr);
	for (int i = 0; i<len; i++) {
		sum += arr[i] - '0';
	}
	return sum;
}
int main() {
	scanf("%s", arr);
	int sum = getsum();
	sprintf(arr, "%d", sum);
	int len = strlen(arr);
	for (int i = 0; i<len; i++) {
		if (i != 0) printf(" ");
		if (arr[i] == '1')
			printf("yi");
		else if (arr[i] == '2')
			printf("er");
		else if (arr[i] == '3')
			printf("san");
		else if (arr[i] == '4')
			printf("si");
		else if (arr[i] == '5')
			printf("wu");
		else if (arr[i] == '6')
			printf("liu");
		else if (arr[i] == '7')
			printf("qi");
		else if (arr[i] == '8')
			printf("ba");
		else if (arr[i] == '9')
			printf("jiu");
		else if (arr[i] == '0')
			printf("ling");
	}
	return 0;
}

2，简化代码，用如下代码简化输出部分的ifelse结构

char data[10][20] = { "ling","yi","er","san","si","wu","liu","qi","ba","jiu" };
printf("%s", data[arr[i] - '0']);