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  • 信号灯法

    信号灯法

    //测试生产者消费者问题2:信号灯法,标志位解决
    
    public class TestPc2 {
        public static void main(String[] args) {
            TV tv = new TV();
            new Player(tv).start();
            new Watcher(tv).start();
        }
    
    }
    
    //生产者-->演员
    class Player extends Thread{
        TV tv;
        public Player(TV tv){
            this.tv = tv;
        }
    
        @Override
        public void run() {
            for (int i = 0; i < 20; i++) {
                if (i%2==0){
                    this.tv.play("快乐大本营播放中");
                }else {
                    this.tv.play("抖音:记录美好生活");
                }
            }
        }
    }
    
    //消费者-->观众
    class Watcher extends Thread{
        TV tv;
        public Watcher(TV tv){
            this.tv = tv;
        }
    
        @Override
        public void run() {
            for (int i = 0; i < 20; i++) {
                tv.watch();
            }
        }
    }
    
    //产品-->节目
    class TV{
        //演员表演,观众等待
        //观众观看,演员等待
        String voice;//表演的节目
        boolean flag = true;
    
        //表演
        public synchronized void play(String voice){
    
            if (!flag){
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
    
            System.out.println("演员表演了:"+voice);
            //通知观众观看
            this.notifyAll();//通知唤醒
            this.voice = voice;
            this.flag = !this.flag;
        }
    
        //观看
        public synchronized void watch(){
            if (flag){
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            System.out.println("观看了:"+voice);
            //通知演员表演
            this.notifyAll();
            this.flag = !this.flag;
        }
    
    }
    
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  • 原文地址:https://www.cnblogs.com/helloxiaolu/p/13324690.html
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