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  • swift 基础-4

    函数:完成特定任务的代码块,通过名字来表示函数做什么

    func 函数名(形参:形参类型)->返回类型

    command +option+0 隐藏右边的框

    //定义函数

            func sayHello(name:String)->String{

                let greeting = "hello " + name + "!"

                return greeting

            }

            println(sayHello("Anno"))

            

            // 多个参数

            func minusResult(start:Int,end:Int)->Int{

                return end - start

            }

            println(minusResult(1,10))

            

            //无参数

            func sayHelloWorld() ->String{

                return "Helo World"

            }

            println(sayHelloWorld())

            

            // 无返回值 Void = 空元组(tuple

            func sayGoodbye(name:String){

                println("Goodby,(name)")

            }

            println(sayGoodbye("Dave"))

            // 多重返回值函数

            func count(str:String) ->(vs:Int,cs:Int,os:Int){

                var vowels = 0,consonants = 0,others = 0

                for Character in str{

                    switch String(Character).lowercaseString{

                        case "a","e","i","o","u":

                        ++vowels

                        case "b","c","d","f","g","h","j","k","l","m","n","p","q","t","s","t","v","w","x","y","z":

                        ++consonants

                    default:

                        ++others

                    }

                }

                return (vowels,consonants,others)

            }

            let total = count("some arbitrary string!")

            println("(total.vs) vowels and (total.cs) consonants")

            

            // 外部参数名 把两个字符串连在一起

            func join(s1:String, s2:String,joiner:String) ->String{

                return s1 + joiner + s2

            }

            println(join("hello","world",","))

        // 不使用外部参数的时候,这三个参数不清楚到底是干什么的

            func joins(outSting s1:String,toSting s2:String, withJoiner joiner:String) ->String{

                return s1 + joiner + s2

            }

            println(joins(outSting:"hello",toSting:"world",withJoiner:","))

            // 带来问题:调用函数的时候 写太多,解决办法 看下边

            

            // 简写 外部参数名  参数名前 #

    //        func joins1(outSting s1:String,toSting s2:String, withJoiner joiner:String) ->String{

    //            return s1 + joiner + s2

    //        }

    //        println(joins1(outSting:"hello",toSting:"world",withJoiner:","))

            func containsCharacter(#string:String,#characterToFind:Character) ->Bool{

                for character in string{

                    if character == characterToFind{

                        return true

                    }

                }

                return false

            }

            let containsAVee = containsCharacter(string: "qwertyuiop", characterToFind: "y")

            println(containsAVee)

            

            // 给默认参数

            func joinss(outSting s1:String,toSting s2:String, withJoiner joiner:String = ",") ->String{

                return s1 + joiner + s2

            }

            // 第三个参数 没写 直接使用默认值

            let str1 = joinss(outSting: "nihao", toSting: "heri")

            println(str1)

            

            //  注意会出错 

            func joinbb(outSting s1:String,toSting s2:String, withJoiner joiner:String = "") ->String{

                return s1 + joiner + s2

            }

            // 第三个参数 没写 直接使用默认值

            let str2 = joinbb( outSting: "haha", toSting: "zheli", withJoiner: "+")

            println(str2)

            // 可变参数   传入不确定数量来输入参数     变量名类型 ...  = 数组常量

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  • 原文地址:https://www.cnblogs.com/heri/p/4397222.html
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