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  • 3sum closest

    1. Question

    给定一个整型数组和key,找三个数,使其和与key最相近,返回这三个数的和。(假设至少会有一个解)

    Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
    
        For example, given array S = {-1 2 1 -4}, and target = 1.
    
        The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

    2. Solution(O(n2))

    相似题:3Sum

    考虑特殊情况:

    • 数组元素个数<3

    采用twoSum的双指针法,只需额外维护一个最近的三个数和即可。

    public class Solution {
        public int threeSumClosest( int[] nums, int target ){
            int len = nums.length;
            if( len<3 )
                return 0;
            
            Arrays.sort( nums );
            int closestThree = nums[0] + nums[1] + nums[2];
            for( int i=0; i<len-2; i++ ){
                //use two pointers find the closest two for i
                for( int j=i+1, k=len-1; j<k; ){
                    int nowThree = nums[i] + nums[j] + nums[k];
                    int distance = target - nowThree;
                    //update j & k
                    if( distance < 0 )
                        k--;
                    else if( distance > 0 )
                        j++;
                    //find the exact three integers that sum to target
                    else
                        return target;
                    //update closestThree
                    if( Math.abs( distance) < Math.abs( target - closestThree))
                        closestThree = nowThree;
                }
            }
            return closestThree;
        }
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/hf-cherish/p/4607017.html
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