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  • 打印NxN的矩阵

    找出规律,并打印出一个NxN的矩阵,规律就是从首坐标开始顺时针依次增大:

     1 #include<iostream>
     2 #include<vector>
     3 
     4 using namespace std;
     5 
     6 int main(void)
     7 {
     8 
     9     int N;
    10     cout << "Input a num:" << endl;
    11     cin >> N;
    12     while (N < 0)
    13     {
    14         cout << "invalid input!!!" << endl;
    15         cout << "input again!!!" << endl;
    16         cin >> N;
    17     }
    18     if (N == 0)
    19     {
    20         cout << 0;
    21         return 0;
    22     }
    23 
    24     vector<vector<int> > p(N);
    25     for (int i = 0; i < N; i++)
    26     {
    27         p[i].resize(N);//设置N*N的数组
    28     }
    29     int k = 0;
    30     for (int j = 0; j < N / 2;j++)
    31     {
    32         for (int i = j; i < N - j; i++)
    33         {
    34             p[j][i] = k;
    35             k++;
    36         }
    37         for (int i = 1 + j; i < N - j; i++)
    38         {
    39             p[i][N - j - 1] = k;
    40             k++;
    41         }
    42         for (int i = N - 2 - j; i >= j; i--)
    43         {
    44             p[N - 1 - j][i] = k;
    45             k++;
    46         }
    47         for (int i = N - 2-j; i >j; i--)
    48         {
    49             p[i][j] = k;
    50             k++;
    51         }
    52     }
    53     if (N % 2 == 1)
    54     {
    55         p[N / 2][N / 2] = k;
    56     }
    57 
    58     for (int i = 0; i < N; i++)
    59     {
    60         for (int j = 0; j < N; j++)
    61         {
    62             cout << p[i][j] << "	";
    63         }
    64         cout << endl;
    65     }
    66     return 0;
    67 }
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  • 原文地址:https://www.cnblogs.com/hhboboy/p/5516859.html
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