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  • 四分历python实现

    根据一个新加坡人的c代码改写成python代码

      1 ''' 四分历'''
      2 
      3 # 
      4 zq = 0
      5 month = 0
      6 
      7 def main():
      8     global month
      9     year = 1
     10     rb_year = 0
     11     moon = 0  # number of new moon since beginning of ru bu year.
     12     tmonth = 0
     13     continues = False
     14 
     15     while year != 0:
     16         year = int(input("
    Please Enter a year to do computation (range:85~236, 0 to exit):"))
     17 
     18         if year == 0: 
     19             return
     20         if year < 85 or year > 236:
     21             print("
    Calculation of Si Fen Li doesn't apply to your input value.")
     22             input("
    Press Enter to continue.")
     23             #getch(continues);
     24             continue
     25 
     26         rb_year = (year + 9281) % 76
     27         tmonth = 14 + Leap_y(rb_year)
     28 
     29         print("月	朔	望	长度	中气	时间	时间	时间")
     30         print("- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -")
     31 
     32         month = 11
     33         #zq = 0
     34         for moon in range(1, tmonth + 1):
     35             if moon % 8 == 0:
     36                 #print("
    ")
     37                 pass
     38             print_s(rb_year, moon)
     39             month += 1
     40             if month > 12:
     41                 month = 1
     42 
     43         input("
    Press Enter to continue.")
     44 
     45 # 润年
     46 def Leap_y( rbyear):
     47     isLeap = 0
     48     if ((rbyear - 1) * 235 ) % 19 >= 12:
     49         isLeap = 1
     50     return isLeap
     51 
     52 # 润月
     53 def Leap_m(rbyear, month):
     54     isLeap = 0
     55     completed_month = (rbyear - 1) * (235.0/19.0) + (month - 1)
     56     acd_first = (completed_month * (29.0+499.0/940.0) )
     57     acd_last  = ((completed_month + 1.0) * (29.0+499.0/940.0) )
     58     qi_first  = int(acd_first)/(30.0+14.0/32.0)
     59     qi_last   = int(acd_last) / (30.0+14.0/32.0)
     60 
     61     if qi_first - int(qi_first) != 0:
     62         if int(qi_first) == int(qi_last) or qi_last == int(qi_last):
     63             isLeap = 1
     64 
     65     return isLeap
     66 
     67 
     68 # 打印结果
     69 def print_s(rbyear, moon):
     70     global zq
     71     global month
     72     name_s = acd_shuo(rbyear, moon)
     73     name_w = acd_wang(rbyear, moon)
     74     time_s = ( acd_shuo(rbyear, moon) - float(name_s) ) * 24.0
     75     time_w = ( acd_wang(rbyear, moon) - float(name_w) ) * 24.0
     76     length = int(acd_shuo(rbyear, moon + 1)) - name_s
     77 
     78     if Leap_m(rbyear, moon) == 0:    #if is not a leap month.
     79         zq += 1
     80         name_q = acd_qi(rbyear, zq);
     81         time_q = ( acd_qi(rbyear, zq) - (float)(name_q) ) * 24.0
     82         print("{}	1	{:.1f}	{:.3f}	{:.1f}	{:.3f}	{:.3f}	{:.1f}".format(month, time_s, name_w - name_s + 1, time_w, length, name_q - name_s + 1, time_q))
     83     else:
     84         month -= 1
     85         print("{}(Leap)	1	{:.1f}	{:.3f}	{:.1f}	{:.3f}".format(month, time_s, name_w - name_s + 1, time_w, length))
     86 
     87 
     88 #
     89 def acd_shuo(rbyear, moon):
     90     completed_month = ((rbyear - 1) * 235 / 19) + moon - 1
     91     return completed_month * (29.0+499.0/940.0)
     92 
     93 #
     94 def acd_wang(rbyear, moon):
     95     completed_month = ((rbyear - 1) * 235 / 19) + moon - 1
     96     return (completed_month + 0.5) * (29.0+499.0/940.0)
     97 
     98 #
     99 def acd_qi(rbyear, qi):
    100     completed_qi = ((rbyear - 1) * 12) + qi - 1
    101     return completed_qi * (30.0+14.0/32.0)
    102 
    103 
    104 if __name__ == '__main__':
    105     main()
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  • 原文地址:https://www.cnblogs.com/hhh5460/p/4304502.html
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