zoukankan      html  css  js  c++  java
  • 完美立方2810

    完美立方

     OpenJ_Bailian - 2810 

    Time limit1000 ms     Memory limit65536 kB  OS Linux  Source1543

    形如a3= b3 + c3 + d3的等式被称为完美立方等式。例如123= 63 + 83 + 103 。编写一个程序,对任给的正整数N (N≤100),寻找所有的四元组(a, b, c, d),使得a3 = b3 + c3 + d3,其中a,b,c,d 大于 1, 小于等于N,且b<=c<=d。

    Input一个正整数N (N≤100)。Output每行输出一个完美立方。输出格式为: 
    Cube = a, Triple = (b,c,d) 
    其中a,b,c,d所在位置分别用实际求出四元组值代入。 

    请按照a的值,从小到大依次输出。当两个完美立方等式中a的值相同,则b值小的优先输出、仍相同则c值小的优先输出、再相同则d值小的先输出。

    Sample Input

    24

    Sample Output

    Cube = 6, Triple = (3,4,5)
    Cube = 12, Triple = (6,8,10)
    Cube = 18, Triple = (2,12,16)
    Cube = 18, Triple = (9,12,15)
    Cube = 19, Triple = (3,10,18)
    Cube = 20, Triple = (7,14,17)
    Cube = 24, Triple = (12,16,20)
     1 #include <iostream>
     2 using namespace std;
     3 
     4 //#define cube(a) a * a * a
     5 
     6 
     7 int main()
     8 {
     9     int a, b, c, d, N;
    10     cin >> N;
    11     int cube[101];
    12     for (int i = 2; i < 101; i++)
    13         cube[i] = i * i * i;
    14 
    15     for (a = 2; a <= N; a++)
    16     for (b = 2; b < a; b++)
    17     for (c = b; c < a; c++)
    18     for (d = c; d < a; d++)
    19     if (cube[b] + cube[c] + cube[d] == cube[a])
    20         cout << "Cube = " << a << ", Triple = (" << b << "," << c << "," << d << ")" << endl;
    21 
    22     return 0;
    23 }
  • 相关阅读:
    在Wince下使用钩子函数
    WinCE下钩子应用(一)——WinCE 下实时捕获键盘消息
    记录此刻
    常用数列
    百度之星度度熊拼三角
    笛卡尔定理
    Lucas定理
    简单概念
    Unknown Treasure Lucas+中国剩余定理+快速乘
    2017ccpc杭州站 Problem B. Master of Phi
  • 原文地址:https://www.cnblogs.com/hi3254014978/p/10451547.html
Copyright © 2011-2022 走看看