字符串和整形数组的相互转化（JAVA程序）

package te;
public class StringConvert {
    static int[] a = {0,1,1,0,1,1,0,2};
    static String s = "0011223344";
    public static void main(String[] args) {
        StringConvert sc = new StringConvert();
        System.out.println(sc.intArray2Str(a));
        int[] b = sc.str2IntArray(s);
        for(int i=0; i<b.length; i++) {
            System.out.print(b[i]);
        }    
    }
    
    String intArray2Str(int[] a) {
        
        int len = a.length;
        String str="";
        for(int i=0;i<len; i++) {
            str+=String.valueOf(a[i]);
        }        
        return str;    
    }
    
    int[] str2IntArray(String str) {
        int len = str.length();
        int[] a = new int[len];
        char[] c = str.toCharArray();
        for(int i=0; i<len; i++) {
            a[i] = c[i]-'0';
        }    
        return a;    
    }

}

结果

01101102
0011223344

package te;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class StringConvert {
    static int[] a = {0,1,1,0,1,1,0,2};
    static String s = "0011223340004";
    public static void main(String[] args) {
        StringConvert sc = new StringConvert();
        System.out.println(sc.intArray2Str(a));
        int[] b = sc.str2IntArray(s);
        for(int i=0; i<b.length; i++) {
            System.out.print(b[i]);
        }
        System.out.print('
');
        sc.indexsof(s);
    }
    
    String intArray2Str(int[] a) {
        
        int len = a.length;
        String str="";
        for(int i=0;i<len; i++) {
            str+=String.valueOf(a[i]);
        }        
        return str;    
    }
    
    int[] str2IntArray(String str) {
        int len = str.length();
        int[] a = new int[len];
        char[] c = str.toCharArray();
        for(int i=0; i<len; i++) {
            a[i] = c[i]-'0';
        }    
        return a;    
    }
    int[] indexsof(String s) {
        
         Pattern p = Pattern.compile("[0]");
         Matcher m = p.matcher(s);
         while(m.find()) {
             System.out.println(m.start());
         }

        return null;
        
    }
}

从一个字符串中找到符合要求字符串的所有位置