ArrayList的sublist注意

void testArrayList(){
        String []appname ={"联系人","相机","电话","收音机","手电筒","更多"};
        String s_appname = null;
        List<Map<String, Object>>  gv_applist = new ArrayList<Map<String,Object>>();
        for(int i=0; i<appname.length;i++) {
            
            s_appname = appname[i];
            Map<String, Object> map = new HashMap<String, Object>();
            map.put("appname", s_appname); 
            gv_applist.add(map); 
         }
 
        
        List<Map<String, Object>>  templist1 = new ArrayList<Map<String, Object>>();
        templist1 = gv_applist.subList(0, 4);
        System.out.println(templist1.size());//输出4
//        gv_applist.remove(2);
        templist1.size();//报错 java.util.ConcurrentModificationException
        
        
        List<Map<String, Object>>  templist2 = new ArrayList<Map<String, Object>>(gv_applist.subList(0, 4));    
        System.out.println(templist2.size());//输出4    
        gv_applist.remove(2);
        System.out.println(templist2.size());//输出4,这种方式子链表不受母链表影响，母链表可以任意操作
        
        templist2.remove(2);
        System.out.println(templist2.size());//输出3


    }