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  • UVA 12849 Mother’s Jam Puzzle( 高斯消元 )


    题目: http://uva.onlinejudge.org/external/128/12849.pdf

    #include <bits/stdc++.h>
    using namespace std;
    typedef long long LL ;
    typedef unsigned long long ULL ;
    typedef pair<int,int> pii;
    #define X first
    #define Y second
    const int N = 5 ;
    const int mod = 1e9+7 ;
    const double K = 100000;
    double A[N][N] ;
    
    void solve( int n ) {
        int i , k , j , r ;
        for( i = 0 ; i < n ; ++i ) {
            r = i ;
            for( j = i + 1 ; j < n ; ++j )
                if( fabs(A[j][i]) > fabs( A[r][i] ) ) r = j ;
    
            if( r != i ) for( j = 0 ; j <= n ; ++j ) swap( A[r][j] , A[i][j] ) ;
    
            for( j = n ; j >= i ; j-- ) {
                for( k = i + 1 ; k < n ; ++k ) {
                    A[k][j] -= A[k][i] / A[i][i] * A[i][j] ;
                }
            }
        }
        for( i = n-1 ; i >=0 ; i-- ) {
            for( j = i + 1 ; j < n ; ++j )
                A[i][n] -= A[j][n] * A[i][j] ;
            A[i][n] /= A[i][i];
        }
    }
    
    int Run() {
        int _ , cas = 1 ; scanf("%d",&_);
        while( _-- ) {
            printf("Case %d: ",cas++);
            for( int i = 0 ; i < 3 ; ++i ) {
                for( int j = 0 ; j < 4 ; ++j ) {
                    scanf("%lf",&A[i][j]);
                    A[i][j] *= K ;
                }
            }
            solve(3) ;
            printf("%.2lf %.2lf %.2lf
    ",A[0][3],A[1][3],A[2][3]);
        }
        return 0 ;
    }
    
    int main()
    {
        #ifdef LOCAL
            freopen("in","r",stdin);
        #endif
        ios::sync_with_stdio(0);
        return Run();
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/hlmark/p/4371418.html
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