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  • java 数组的复制、反转、查找(线性查找、二分法查找)

    public class Demo2 {
        public static void main(String[] args) {        
            /*
             * 算法的考查:数组的复制、反转、查找(线性查找、二分法查找)
             *
             *
             */
    
    
            String[] arr=new String[]{"AA","BB","CC","DD","EE","FF"};
    //        数组的复制(区别于数组变量的赋值:arr1 = arr)
            String[] arr1=new String[arr.length];
            for(int i=0;i<arr1.length;i++){
                arr1[i]=arr[i];
                System.out.println(arr1[i]);
            }
    
    //        数组的反转
    /*//        方式一
            for(int i=0;i<arr1.length/2;i++){
                String temp=arr1[i];
                arr1[i]=arr1[arr1.length-1-i];
                arr1[arr1.length-1-i]=temp;
            }
    //    遍历
            for(int i=0;i<arr1.length;i++){
                System.out.print(arr1[i]);
            }*/
    
    /*//        方式二:
            int i=0;
            int j=arr1.length-1;
            while (i<j){
                String temp=arr1[i];
                arr1[i]=arr1[j];
                arr1[j]=temp;
                i++;
                j--;
            }
    //        遍历
            for(int a=0;a<arr1.length;a++){
                System.out.print(arr1[a]);
            }*/
    
    /*//        方式三
            for(int i=0,j=arr.length-1;i<j;i++,j--){
                String temp=arr[i];
                arr[i]=arr[j];
                arr[j]=temp;
            }
            for(int a=0;a<arr.length;a++){
                System.out.print(arr[a]);
            }*/
    
            System.out.println();
            //查找(或搜索)
            //线性查找:
            String dest = "BB";
            dest = "CC";
    
            boolean isFlag = true;
    
            for(int i = 0;i < arr.length;i++){
    
                if(dest.equals(arr[i])){
                    System.out.println("找到了指定的元素,位置为:" + i);
                    isFlag = false;
                    break;
                }
    
            }
            if(isFlag){
                System.out.println("很遗憾,没有找到的啦!");
    
            }
            //二分法查找:(熟悉)
            //前提:所要查找的数组必须有序。
            int[] arr2 = new int[]{-98,-34,2,34,54,66,79,105,210,333};
    
            int dest1 = -34;
            dest1 = 35;
            int head = 0;//初始的首索引
            int end = arr2.length - 1;//初始的末索引
            boolean isFlag1 = true;
            while(head <= end){
    
                int middle = (head + end)/2;
    
                if(dest1 == arr2[middle]){
                    System.out.println("找到了指定的元素,位置为:" + middle);
                    isFlag1 = false;
                    break;
                }else if(arr2[middle] > dest1){
                    end = middle - 1;
                }else{//arr2[middle] < dest1
                    head = middle + 1;
                }
    
    
            }
    
            if(isFlag1){
                System.out.println("很遗憾,没有找到的啦!");
            }
    
    
    
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/hr-7/p/14708004.html
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