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  • LeetCode 58 Spiral Matrix II

    Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.

    For example,
    Given n = 3,

    You should return the following matrix:
    [
     [ 1, 2, 3 ],
     [ 8, 9, 4 ],
     [ 7, 6, 5 ]
    ]
    思路:与上一篇类似。仅仅要不越界就ok
    public class Solution {
    	public int[][] generateMatrix(int n) {
    	    if (n == 0)
    			return new int[0][0];
    
    		int[][] matrix = new int[n][n];
    		int x1 = 0;
    		int y1 = 0;
    		int x2 = matrix.length - 1;
    		int y2 = matrix[0].length - 1;
    		int i = 0, j = 1;
    		while (x1 <= x2 && y1 <= y2) {
    			// up row
    			for (i = y1; i <= y2; ++i, j++)
    				matrix[x1][i] = j;
    			// right column
    			for (i = x1 + 1; i <= x2; ++i, j++)
    				matrix[i][y2] = j;
    			// bottom row
    			for (i = y2 - 1; x2 != x1 && i >= y1; --i, j++)
    				matrix[x2][i] = j;
    			// left column
    			for (i = x2 - 1; y1 != y2 && i > x1; --i, j++)
    				matrix[i][y1] = j;
    
    			x1++;
    			y1++;
    			x2--;
    			y2--;
    		}
    		return matrix;
    	}
    }


    版权声明:本文博主原创文章,博客,未经同意不得转载。

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  • 原文地址:https://www.cnblogs.com/hrhguanli/p/4854147.html
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