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  • HDU 5645

    DZY Loves Balls

    Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)
    Total Submission(s): 320    Accepted Submission(s): 194


    Problem Description
    DZY loves playing balls.

    He has n balls in a big box. On each ball there is an integer written.

    One day he decides to pick two balls from the box. First he randomly picks a ball from the box, and names it A . Next, without putting A back into the box, he randomly picks another ball from the box, and names it B .

    If the number written on A is strictly greater than the number on B , he will feel happy.

    Now you are given the numbers on each ball. Please calculate the probability that he feels happy.
     
    Input
    First line contains t denoting the number of testcases.

    t testcases follow. In each testcase, first line contains n , second line contains n space-separated positive integers ai , denoting the numbers on the balls.

    (1t300,2n300,1ai300 )
     
    Output
    For each testcase, output a real number with 6 decimal places.
     
    Sample Input
    2
    3
    1 2 3
    3
    100 100 100
     
    Sample Output
    0.500000
    0.000000
     
    Source
    昨天参加了蓝桥  感觉不是很理想 等出结果吧
    补 前天的bc
    因为数据规模很小,所以直接用O(n2)​​)时间求出有多少对(i,j)满足ai<aj,然后再除以n(n−1)/2即可。
     
     1 #include<iostream>
     2 #include<algorithm>
     3 #include<cstring>
     4 #include<cstdio>
     5 using namespace std;
     6 int t;
     7 int n;
     8 int a[305];
     9 int main()
    10 {
    11     scanf("%d",&t);
    12     for(int i=1;i<=t;i++)
    13     {
    14         scanf("%d",&n);
    15         memset(a,0,sizeof(a));
    16         int jishu=0;
    17         for(int j=0;j<n;j++)
    18          scanf("%d",&a[j]);
    19          sort(a,a+n);
    20          for(int j=0;j<n;j++)
    21           for(int k=j+1;k<n;k++)
    22           {
    23             if(a[k]>a[j])
    24             jishu++;
    25           }
    26           double ans=n*(n-1);
    27           printf("%.6f
    ",jishu/ans); 
    28     }
    29 return 0;
    30 }
    View Code
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  • 原文地址:https://www.cnblogs.com/hsd-/p/5303915.html
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