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  • Asp.netMVC模型

    Model负责在View和控制器之间进行数据的传递:用户输入的内容封装为Model对象,发给Controller;要显示的数据有Controller放到Model中,然后扔给View去显示。Controller不直接和View进行交互。

    查询id>1的狗有如下两种方法:

    lambda写法:var r=dogs.where(d=>d.id>1)

    Linq写法:var r2=from d in dogs   where d.id>1 select d;

    Linq基本语法:以from item in items开始,items为待处理的集合,item为每一项的变量名;最后要加上select,表示结果的数据;记得select一定要放在最后

    All---------Grouped

    List<Product>products=GetProductList();

    var productGroups=from p in products

                                   group p by p.Category into g

                                   where g.All(p=>p.UnitsInStock>0)

                                  select new { Category =g.Key, Products = g };

    Count-----Simple

    获取列表中没有重复的元素数量

    int []factors={ 2, 2, 3, 5, 5};

    int unique=factors.Distinct().Count();

    Console.WriteLine("There are {0} unique factors",unique);

    Count---Nested

    List<Customer> customers=GetCustomerList();

    var orderCounts=from c in customers

                                select new{ c.CustomerID,OrderCount=c.Orders.Count() };

    Count --------Grouped

    List<Product>products=GetProductList();

    var categoryCounts=from p in products

                                     group p by p.Category into g

                                     select new { Category=g.Key,ProductCount=g.Count() };

    Sum----Grouped

    List<Product>products=GetProductList();

    var categories=from p in products

                             group p by p.Category into g

                             select new { Category=g.Key, TotalUnitsInstock=g.Sum(p=>p.UnitsInStock) };

    ObjectDumper.Write(categories);

    Min-----Projection

    string[]words={"cherry","apple","blueberry"};

    int shortestWord=words.Min(w=>w.Length);

    Console.WriteLine("The shortest word is {0} characters long.",shortestWord);

    Min-----Grouped

    List<Product>products=GetProductList();

    var categories=from p in products

                            group p by p.Category into g

                             select new { Category=g.Key , CheapestPrice=g.Min(p=>p.UnitPrice) };

    ObjectDumper.Write(categories);

    Min------Elements

    List<Product>prodducts=GetProductList();

    var categories=from p in products

                             group p by p.Category into g

                             let minPrice=g.Min(p=>p.UnitPrice)

                              select new { Category=g.Key,CheapestProducts=g.Where(p=>p.UnitPrice==minPrice) };

    Max----Projection

    string [ ] words={ "cherry", "apple", "blueberry" };

    int longestLength=words.Max(w=>w.Length);

    Console.WriteLine("The longest word is {0} characters long",longestLength);

    Max-----Grouped

    List<Product>products=GetProductList();

    var categories=from p in products

                             group p by p.Category into g

                              select new {Category=g.Key,MostExpensivePrice=g.Max(p=>p.UnitPrice) };

    Max------Elements

    List<Product>products=GetProductList();

    var categories=from p in products

                             group p by p.Category into g

                              let maxPrice=g.Max(p=>p.UnitPrice)

                              select new { Category=g.Key, MostExpensiveProducts=g.Where(p=>p.UnitPrice==maxPrice) };

    ObjectDumper.Write(categories,1);

    Average ---Projection

    string[] words={"cherry", "apple", "blueberry"};

    double averageLength=words.Average(w=>w.Length);

    Console.WriteLine("The average word length is {0} characters.",averageLength);

    Average----Grouped

    List<Product>products=GetProductList();

    var categories=from p in products

                             group p by p.Category into g

                              select new {Category=g.Key, AveragePrice=g.Average(p=>p.UnitPrice) };

    Aggregate----Simple

    这个例子是数组中所有的元素相乘,求出最终的积

    double[] doubles={1.7, 2.3, 1.9, 4.1, 2.9};

    double product=doubles.Aggregate((runningProduct,nextFactor)=>runningProduct*nextFactor);

    Console.WriteLine("Total product of all numbers:{0}",product);

    Concat----1

    求两个集合的合集

    int[] numbersA={0,2,4,5,6,8,9};

    int[] numbersB={1,3,5,7,8};

    var allNumbers=numbersA.Concat(numbersB);

    Console.WriteLine("All numbers from both arrays:");

    foreach(var n in allNumbers){

    Console.WriteLine(n);

    }

    Concat---2

    List<Customer>customers=GetCustomerList();

    List<Product>products=GetProductList();

    var customerNames=from c in customers

                                      select c.CompanyName;

    var productNames=from p in products

                                    select p.ProductName;

    var allNames=customerNames.Concat(productNames);

    Console.WriteLine("Customer and product names:");

    foreach(var n in allNames){

    Console.WriteLine(n);

    }

    SequenceEqual--1

    var wordA=new string[]{ "cherry", "apple", "blueberry"};

    var wordB=new string[]{"cherry", "apple", "blueberry"};

    bool match=wordsA.SequenceEqual(wordsB);

    Console.WriteLine("The sequences match: {0} ",match);

    SequenceEqual--2

    var wordsA=new string[]{"cherry", "apple", "blueberry"};

    var wordsB=new string[]{"apple","blueberry","cherry"};

    bool match=wordsA.SequenceEqual(wordsB);

    Console.WriteLine("The sequences match:{0}", match);

    List集合Group by 查询

    var groupList=chRCheckConfirmList.GroupBy(x=>new {x.CompanyId, x.Type, x.ChRCheckItemConfigId}).select(group=>new { Keys=group.Key, TotalScore=group.Sum(p=>p.Score)})

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  • 原文地址:https://www.cnblogs.com/huanggenwei/p/10635332.html
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