题目：
Age Sort You are given the ages (in years) of all people of a country with at least 1 year of age. You know that no individual in that country lives for 100 or more years. Now, you are given a very simple task of sorting all the ages in ascending order.
Input
There are multiple test cases in the input file. Each case starts with an integer n (0 < n ≤ 2000000), the total number of people. In the next line, there are n integers indicating the ages. Input is terminated with a case where n = 0. This case should not be processed.
Output
For each case, print a line with n space separated integers. These integers are the ages of that country sorted in ascending order.
Warning: Input Data is pretty big (∼ 25 MB) so use faster IO.
题目大意：输入N个数 将它们按从小到大排序，遇到输入0程序结束
解题思路：讲输入的N个数存储到数组中，利用头文件algorithm中的sort（）函数排列，再输出；
代码：
1 #include<iostream> 2 #include<cstdio> 3 #include<algorithm> 4 using namespace std; 5 int main() 6 { 7 int* a; 8 int n; 9 while(cin>>n) 10 { 11 if(n>0&&n<=2000000) 12 { 13 a=new int[n]; 14 for(int i=0;i<n;i++) 15 scanf("%d",&a[i]); 16 sort(a,a+n); 17 for(int j=0;j<n;j++) 18 { 19 if(j!=(n-1)) 20 printf("%d ",a[j]); 21 else printf("%d",a[j]); 22 } 23 printf(" "); 24 } 25 else break; 26 } 27 return 0; 28 }