zoukankan      html  css  js  c++  java
  • JAXB

    The annotation XmlSchemaType defines a mapping between an arbitrary Java type and a simple schema built-in type. Most of the time the default mapping is satisfactory, but every now and then an alternative may be more convenient. Let's assume that the processing of chunks of text requires their extension, either after unmarshalling or before the emitting marshalling. For this, a StringBuffer is better than String, which is the default mapping for xs:string. Below are the essential Java classes, one defining TextType as a container for a string, and the type adapter class for the simple conversion between String and StringBuffer. Notice that the latter class is specified in a separate annotation, i.e.,XmlJavaTypeAdapter.

    public class TextType {
        @XmlElement
        @XmlSchemaType(name="string")
        @XmlJavaTypeAdapter( String2StrBuf.class )
        public StringBuffer strbuf;
    }
    
    public class String2StrBuf
        extends XmlAdapter<String,StringBuffer> {
        @Override
        public String marshal( StringBuffer strbuf ){
            return strbuf.toString();
        }
        @Override
        public StringBuffer unmarshal( String string ){
            return new StringBuffer( string );
        }
    }

    Within the Java code that unmarshals or marshals an instance document, TextType elements are now StringBuffers, e.g.:

    TextType text = new TextType();
    text.strbuf = new StringBuffer( "This is the house" );
    // ...
    text.strbuf.append( " that Jack built." );

    Such a type mapping can be defined either for an individual element or for all occurrences within a package. If you need multiple mappings at package level, you'll have to bundle theXmlSchemaType annotations in an XmlSchemaTypes (note the plural) annotation, and the XmlJavaTypeAdapter annotiations are packed into a single XmlJavaTypeAdapters annotation.

  • 相关阅读:
    ssh
    ssh免密码登陆
    滑雪[dp]
    Help Jimmy[dp]
    动态规划 [子序列问题]
    最佳加法表达式 [dp]
    求排列的逆序数[归并排序]
    输出前m大个数,时间复杂度O(n+mlog(m)) [快排]
    不会递归?五道例题教你如何递归
    函数模板的琐碎笔记
  • 原文地址:https://www.cnblogs.com/huey/p/5512379.html
Copyright © 2011-2022 走看看