zoukankan      html  css  js  c++  java
  • [LeetCode] 71. Simplify Path

    [LeetCode] 71. Simplify Path

    题目

    Given a string path, which is an absolute path (starting with a slash '/') to a file or directory in a Unix-style file system, convert it to the simplified canonical path.

    In a Unix-style file system, a period '.' refers to the current directory, a double period '..' refers to the directory up a level, and any multiple consecutive slashes (i.e. '//') are treated as a single slash '/'. For this problem, any other format of periods such as '...' are treated as file/directory names.

    The canonical path should have the following format:

    The path starts with a single slash '/'.
    Any two directories are separated by a single slash '/'.
    The path does not end with a trailing '/'.
    The path only contains the directories on the path from the root directory to the target file or directory (i.e., no period '.' or double period '..')
    Return the simplified canonical path.

    Example 1:

    Input: path = "/home/"
    Output: "/home"
    Explanation: Note that there is no trailing slash after the last directory name.
    

    Example 2:

    Input: path = "/../"
    Output: "/"
    Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.
    

    Example 3:

    Input: path = "/home//foo/"
    Output: "/home/foo"
    Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.
    

    Example 4:

    Input: path = "/a/./b/../../c/"
    Output: "/c"
    

    思路

    栈。还有,string 类型可以与 "" 类型判是否相等。

    读入的时候可以用 stringstream 简化代码:

    stringstream ss;
            ss << path;
            string readcache;
            vector<string> filename;
            while( getline(ss,readcache,'/') ){
            }
    

    代码

    class Solution {
    public:
        string simplifyPath(string path) {
            int n = path.size();
            int i = 0;
            vector<string> stk;
            while (i < n) {
                if (path[i] == '/') {
                    i++;
                    continue;
                }
                string now;
                while (i < n && path[i] != '/') {
                    now += path[i];
                    i++;
                }
                if (now == ".") {
                    continue;
                } else if (now == "..") {
                    if (!stk.empty()) {
                        stk.pop_back();
                    }
                }  else {
                    stk.emplace_back(now);
                }
            }
            string ans;
            for (const auto& t: stk) {
                ans += "/" + t;
            }
            if (ans == "") ans = "/";
            return ans;
    
        }
    };
    
    欢迎转载,转载请注明出处!
  • 相关阅读:
    angluar项目里用ant.design组件库做排序功能,可以接口排序,可以组件库做
    echarts箱线图例子分析
    echarts的盒须图问题自问自答自己改造例子
    把数组改成echarts中dataset所需的二维数组
    echarts的markline个性化
    echarts使用dataset实现双y轴效果
    echarts散点图例子scatter-weight折腾记之echarts参数修改
    echarts灵活利用dataset生成多个散点图的例子
    echarts用dataset实现之散点图例子Basic Scatter Chart
    随机字符串生成指定范围内的某个数值
  • 原文地址:https://www.cnblogs.com/huihao/p/15435119.html
Copyright © 2011-2022 走看看