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  • sql查找重复记录

    假设现有一张人员表(表名:Person),若想将姓名、身份证号、住址这三个字段完全相同的记录查找出来,使用

       1:  SELECT p1.*   
       2:  FROM persons   p1,persons   p2   
       3:  WHERE p1.id<>p2.id   
       4:  AND p1.cardid   =   p2.cardid   
       5:  AND p1.pname   =   p2.pname   
       6:  AND p1.address   =   p2.address

    可以实现该功能。

    删除重复记录的SQL语句

    1.用rowid方法

    2.用group by方法

    3.用distinct方法

    1。用rowid方法

    据据oracle带的rowid属性,进行判断,是否存在重复,语句如下:
    查数据:
         select * from table1 a where rowid !=(select   max(rowid)  
         from table1 b where a.name1=b.name1 and a.name2=b.name2......)
    删数据:
        delete   from table1 a where rowid !=(select   max(rowid)  
         from table1 b where a.name1=b.name1 and a.name2=b.name2......)

    2.group by方法

    查数据:
    select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
    group by num
    having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次
    删数据:
    delete from student
    group by num
    having count(num) >1
    这样的话就把所有重复的都删除了。

    3.用distinct方法 -对于小的表比较有用

    create table table_new as   select distinct *   from table1 minux
    truncate table table1;
    insert into table1 select * from table_new;

    查询及删除重复记录的方法大全
    1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

    select * from people
    where peopleId in (select  peopleId  from  people  group  by  peopleId  having  count(peopleId) > 1)

    2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
    delete from people
    where peopleId  in (select  peopleId  from people  group  by  peopleId   having  count(peopleId) > 1)
    and rowid not in (select min(rowid) from  people  group by peopleId  having count(peopleId )>1)

    3、查找表中多余的重复记录(多个字段)
    select * from vitae a
    where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq  having count(*) > 1)

    4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
    delete from vitae a
    where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

    5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
    select * from vitae a
    where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

    (二) 比方说 在A表中存在一个字段“name”,
    而且不同记录之间的“name”值有可能会相同,
    现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
    Select Name,Count(*) From A Group By Name Having Count(*) > 1

    如果还查性别也相同大则如下:
    Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

    (三) 方法一

    declare @max integer,@id integer

    declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1

    open cur_rows

    fetch cur_rows into @id,@max

    while @@fetch_status=0

    begin

    select @max = @max -1

    set rowcount @max

    delete from 表名 where 主字段 = @id

    fetch cur_rows into @id,@max

    end

    close cur_rows

    set rowcount 0

    方法二

    "重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

    1、对于第一种重复,比较容易解决,使用

    select distinct * from tableName

    就可以得到无重复记录的结果集。

    如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除

    select distinct * into #Tmp from tableName

    drop table tableName

    select * into tableName from #Tmp

    drop table #Tmp

    发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

    2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下

    假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

    select identity(int,1,1) as autoID, * into #Tmp from tableName

    select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID

    select * from #Tmp where autoID in(select autoID from #tmp2)

    最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

    (四) 查询重复

    select * from tablename where id in (

    select id from tablename

    group by id

    having count(id) > 1)

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  • 原文地址:https://www.cnblogs.com/hujunli90/p/aa3.html
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