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  • hdu 5328 简单题

    等差和等比各扫一遍即可。

     1 #include <algorithm>
     2 #include <iostream>
     3 #include <cstring>
     4 #include <cstdio>
     5 #include <cmath>
     6 using namespace std;
     7 
     8 const int N = 1000000;
     9 const double eps = 1e-8;
    10 int a[N];
    11 
    12 int main ()
    13 {
    14     int t;
    15     scanf("%d", &t);
    16     while ( t-- )
    17     {
    18         int n;
    19         scanf("%d", &n);
    20         for ( int i = 0; i < n; i++ ) scanf("%d", a + i);
    21         if ( n == 1 || n == 2 )
    22         {
    23             printf("%d
    ", n);
    24             continue;
    25         }
    26         int ans = 2, i = 0;
    27         while ( i < n - 2 )
    28         {
    29             int d = a[i] - a[i + 1];
    30             int j = i + 1;
    31             while ( j < n - 1 && a[j] - a[j + 1] == d )
    32             {
    33                 j++;
    34             }
    35             ans = max( ans, j - i + 1 );
    36             i = j;
    37         }
    38         i = 0;
    39         while ( i < n - 2 )
    40         {
    41             double d = a[i] * 1.0 / a[i + 1];
    42             int j = i + 1;
    43             while ( j < n - 1 && fabs( a[j] * 1.0 / a[j + 1] - d ) < eps )
    44             {
    45                 j++;
    46             }
    47             ans = max( ans, j - i + 1 );
    48             i = j;
    49         }
    50         printf("%d
    ", ans);
    51     }
    52     return 0;
    53 }
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  • 原文地址:https://www.cnblogs.com/huoxiayu/p/4690408.html
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