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  • 【Leetcode】【Easy】Remove Linked List Elements

    Remove all elements from a linked list of integers that have value val.

    Example
    Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
    Return: 1 --> 2 --> 3 --> 4 --> 5

    题目很简单,注意链表首结点有可能更改时,需新建preHead结点,或者使用二维指针的编程方法。

     1 /**
     2  * Definition for singly-linked list.
     3  * struct ListNode {
     4  *     int val;
     5  *     ListNode *next;
     6  *     ListNode(int x) : val(x), next(NULL) {}
     7  * };
     8  */
     9 class Solution {
    10 public:
    11     ListNode* removeElements(ListNode* head, int val) {
    12         if (head == NULL)
    13             return head;
    14             
    15         ListNode* prehead = new ListNode(0);
    16         prehead->next = head;
    17         ListNode* curNode = prehead;
    18         
    19         while (curNode->next != NULL) {
    20             if (curNode->next->val == val)
    21                 curNode->next = curNode->next->next;
    22             else
    23                 curNode = curNode->next;
    24         }
    25         
    26         head = prehead->next;
    27         delete prehead;
    28         return head;
    29     }
    30 };

     

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  • 原文地址:https://www.cnblogs.com/huxiao-tee/p/4582275.html
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