tyvj1424 占卜DIY

大水题一道。纯模拟代码才60行。

#include <cstdio>
using namespace std;

int pile[14][5], open[13];

inline bool ban(char c) {
    if(c <= '9' && c >= '0') return 0;
    if(c == 'A' || c == 'J' || c == 'Q' || c == 'K') {
        return 0;
    }
    return 1;
}

inline int get(char c) {
    if(c == 'A') {
        return 1;
    }
    if(c == 'J') {
        return 11;
    }
    if(c == 'Q') {
        return 12;
    }
    if(c == 'K') {
        return 13;
    }
    if(c == '0') {
        return 10;
    }
    return c - '0';
}

int main() {
    for(int i = 1; i <= 13; i++) {
        for(int j = 4; j >= 1; j--) {
            char c = getchar();
            while(ban(c)) {
                c = getchar();
            }
            pile[i][j] = get(c);
        }
    }
    pile[13][0] = 4;
    while(pile[13][0]) {
        int k = pile[13][pile[13][0]];
        pile[13][0]--;
        while(k != 13) {
            open[k]++;
            pile[k][0]++;
            k = pile[k][pile[k][0]];
        }
    }
    int ans = 0;
    for(int i = 1; i <= 12; i++) {
        ans += (open[i] == 4);
    }
    printf("%d", ans);
    return 0;
}