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  • Codeforces Round #543 (Div. 2, based on Technocup 2019 Final Round)

    A

    签到

    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const int maxn = 150;
    int p[maxn],s[maxn],mx[maxn],c[maxn];
    int main() {
        int n,m,k;
        cin>>n>>m>>k;
        for(int i = 1;i <= n;i++){
            cin>>p[i];
        }
        for(int i = 1;i <= n;i++){
            cin>>s[i];
        }
        for(int i = 1;i <= n;i++){
            if(p[mx[s[i]]] < p[i]){
                mx[s[i]] = i;
            }
        }
        int tot = 0;
        for(int i = 1;i <= k;i++){
            cin>>c[i];
            if(mx[s[c[i]]] != c[i]) tot++;
        }
        cout<<tot;
        return 0;
    }

    B

    签到

    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const int maxn = 1050;
    const int maxm = 200050;
    int a[maxn],vis[maxm];
    int main() {
        int n;
        cin>>n;
        for(int i = 1;i <= n;i++){
            cin>>a[i];
        }
        int ans = 0;
        for(int i = 1;i <= n;i++){
            for(int j = i+1;j <= n;j++){
                vis[a[i]+a[j]]++;
                ans = max(vis[a[i]+a[j]],ans);
            }
        }
        cout<<ans;
        return 0;
    }

    C

    模拟

    #include<bits/stdc++.h>
    using namespace std;
    int n,k,i,j,m,l,b[150],c[150],a[1500],d[1500],f[1500];
    int main()
    {
        for(scanf("%d%d",&n,&k); i<n; ++i,scanf("%d",a+i));
        for(m=-(k=min(k,n)); m<n;)
        {
            for(i=1; i<=k; (c[i]==a[b[i]]?(b[i]=j,d[j]=c[i]=1,++m):++c[i]),++i)
                if(c[i]==a[b[i]])
                    for(j=1; j<=n&&d[j]; ++j);
            for(l=(200*m+n)/(n<<1),i=1; i<=k; f[b[i]]|=(c[i]==l),++i);
        }
        for(k=0,i=1; i<=n; k+=f[i++]);
        printf("%d
    ",k),exit(0);
    }

    D

    尺取法,剪裁区间细节很多

    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const int maxn = 500050;
    int m,n,k,s;
    int a[maxn],b[maxn];
    int t[maxn];
    int now[maxn];
    bool vis[maxn];
    int main() {
        ios::sync_with_stdio(false);
        cin>>m>>k>>n>>s;
        for(int i = 1;i <= m;i++) {
            cin >> a[i];
        }
        for(int i = 1;i <= s;i++){
            cin>>b[i];
            t[b[i]]++;
        }
        if(s > k){
            cout<<-1;
            return 0;
        }
        int lp = 1;
        int wst = 0;
        int ansl = 0,ansr = 0,ans = maxn;
        int cnt=0;
        int lm = m - n*k;
        for(int j = 1;j <= m;j++){
            if(!t[a[j]]){
                wst++;
            }else{
                if(now[a[j]] < t[a[j]])cnt++;
                else wst++;
                now[a[j]]++;
            }
            while(now[a[lp]] > t[a[lp]] || !t[a[lp]]){
                if(lp > j) break;
                if(!t[a[lp]]){
                    wst--;
                    lp++;
                }else{
                    now[a[lp]]--;
                    wst--;
                    lp++;
                }
            }
            if(cnt == s){
                int tl = lp;
                int tr = j;
                int tw = max(tr-tl+1-k,0);
                //int cut = wst + min(tr%k,(tl-1)%k);
                int cut = min((tl-1)%k+tw,tw+(tr-tw)%k);
                if(cut <= lm){
                    ansl = lp;
                    ansr = j;
                    ans = cut;
                }
            }
        }
        if(ans > lm) cout<<"-1";
        else{
            memset(now,0,sizeof(now));
            cout<<m-n*k<<endl;
            int tt = m-n*k;
            for(int i = ansl;i <= ansr;i++){
                if(tt <= 0) break;
                now[a[i]]++;
                if(now[a[i]] > t[a[i]]){
                    vis[i] = true;
                    tt--;
                }
            }
            for(int i = ansl-1;i >= 1 && tt > 0;i--,tt--){
                vis[i] = true;
            }
            for(int i = ansr+1;i <= m && tt > 0;i++,tt--){
                vis[i] = true;
            }
            for(int i = 1;i <= m;i++){
                if(vis[i]) cout<<i<<" ";
            }
            cout<<endl;
        }
        return 0;
    }

    F

    DP

    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const int maxn = 5050;
    char s[maxn];
    int n,a,b;
    int dp[maxn];
    int f[maxn][maxn];
    int main() {
        ios::sync_with_stdio(false);
        cin>>n>>a>>b;
        cin>>(s+1);
        for(int i = 2;i <= n;i++){
            for(int j = 1;j < i;j++){
                if(s[i] == s[j]) f[i][j] = f[i-1][j-1] + 1;
            }
        }
        for(int i = 1;i <= n;i++){
            dp[i] = min(a*i,dp[i-1]+a);
            for(int j = 1;j < i;j++){
                dp[i] = min(dp[i],dp[i-min(i-j,f[i][j])]+b);
            }
        }
        cout<<dp[n];
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/hyfer/p/10666358.html
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