Recover Rotated Sorted Array

Given a rotated sorted array, recover it to sorted array in-place.

 

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Example

[4, 5, 1, 2, 3] -> [1, 2, 3, 4, 5]

Challenge

In-place, O(1) extra space and O(n) time.

Clarification

What is rotated array?

• For example, the orginal array is [1,2,3,4], The rotated array of it can be [1,2,3,4], [2,3,4,1], [3,4,1,2], [4,1,2,3]

    public void recoverRotatedSortedArray(ArrayList<Integer> nums) 
    {
        // write your code
        if(nums.size()==0||nums.size()==1) return;
        int i =0;
        for(i=0; i<nums.size()-1;i++)
        {
            if(nums.get(i)>nums.get(i+1)) break;
        }
        if(i == nums.size()-1) return;
        reverse(nums,0,i);
        reverse(nums,i+1,nums.size()-1);
        reverse(nums,0,nums.size()-1);
        return;
        
        
    }
    
    
    public void reverse(ArrayList<Integer> nums, int left, int right)
    {
        while(left<right)
        {
            int temp = nums.get(left);
            nums.set(left,nums.get(right));
            nums.set(right,temp);
            left++;
            right--;
        
        }
      
        return;
    }